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anonymous

  • one year ago

Can someone help me with this: Find all solutions in the interval [0, 2pi) . 7 tan^3x - 21 tan x = 0

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  1. DanJS
    • one year ago
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    try factoring tan(x) out first, so tan(x) = 0, recall identities to replace tan^2 and tan by sin and cos maybe

  2. DanJS
    • one year ago
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    those probs just play around till you get something in terms of sin and cos using identities and algebra

  3. DanJS
    • one year ago
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    \[7\tan(x)[\tan^2(x) -3]=0\] \[7\tan(x)[\frac{ \sin^2(x) }{ \cos^2(x) } -3]=0\]

  4. anonymous
    • one year ago
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    Here

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  5. anonymous
    • one year ago
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    On the very left its pie.k and not pie

  6. anonymous
    • one year ago
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    @DanJS what are you doing ? :s

  7. anonymous
    • one year ago
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    I mean very right* on the bottom +pie.k

  8. DanJS
    • one year ago
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    lol idk, you have it right, use the unit circle, tan(x)=y/x, remember symmetries if needed for multiple answers over the domain

  9. anonymous
    • one year ago
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    Thats better

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  10. DanJS
    • one year ago
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    looks right

  11. anonymous
    • one year ago
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    Oh and since its limited between ]0,2pie[ Then you write my answer and add for k=0,1,2

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