anonymous
  • anonymous
Can someone help me with this: Find all solutions in the interval [0, 2pi) . 7 tan^3x - 21 tan x = 0
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
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DanJS
  • DanJS
try factoring tan(x) out first, so tan(x) = 0, recall identities to replace tan^2 and tan by sin and cos maybe
DanJS
  • DanJS
those probs just play around till you get something in terms of sin and cos using identities and algebra
DanJS
  • DanJS
\[7\tan(x)[\tan^2(x) -3]=0\] \[7\tan(x)[\frac{ \sin^2(x) }{ \cos^2(x) } -3]=0\]

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anonymous
  • anonymous
Here
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anonymous
  • anonymous
On the very left its pie.k and not pie
anonymous
  • anonymous
@DanJS what are you doing ? :s
anonymous
  • anonymous
I mean very right* on the bottom +pie.k
DanJS
  • DanJS
lol idk, you have it right, use the unit circle, tan(x)=y/x, remember symmetries if needed for multiple answers over the domain
anonymous
  • anonymous
Thats better
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DanJS
  • DanJS
looks right
anonymous
  • anonymous
Oh and since its limited between ]0,2pie[ Then you write my answer and add for k=0,1,2

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