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anonymous

  • one year ago

What is a simpler form of the radical expression? 4^square root 81x^20 y^8

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  1. anonymous
    • one year ago
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    \[\sqrt[4]{81x^{20}y^8}\] like that ?

  2. anonymous
    • one year ago
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    \[\sqrt[4]{81x ^{20}y ^{8}}\]

  3. anonymous
    • one year ago
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    yeah haha you're faster than me

  4. anonymous
    • one year ago
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    this is a lot easier than you think probably how many times does 4 go in to 20?

  5. anonymous
    • one year ago
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    5

  6. anonymous
    • one year ago
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    right and so \[\sqrt[4]{x^{20}}=x^5\]

  7. anonymous
    • one year ago
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    using the same reasoning, what do you think \[\sqrt[4]{y^8}\]is ?

  8. anonymous
    • one year ago
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    2

  9. anonymous
    • one year ago
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    well actually \(y^2\) but you get the idea

  10. anonymous
    • one year ago
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    and all that is left to do is find \(\sqrt[4]{81}\) make a guess

  11. anonymous
    • one year ago
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    hint, it has to be small, since when you multiply it by itself 4 times you get 81

  12. anonymous
    • one year ago
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    9

  13. anonymous
    • one year ago
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    nope too big it is true that \(9^2=81\) but \(9^4=81\times 81\) go smaller

  14. anonymous
    • one year ago
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    3

  15. anonymous
    • one year ago
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    right

  16. anonymous
    • one year ago
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    \[3^4=3\times 3\times 3\times 3=9\times 9=81\]

  17. anonymous
    • one year ago
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    3[x^5]y^2

  18. anonymous
    • one year ago
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    is that the answer?

  19. anonymous
    • one year ago
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    final answer: \[\sqrt[4]{81x^{20}y^8}=3x^5y^2\]the radical is gone

  20. anonymous
    • one year ago
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    yes, you don't need the parentheses though, just write them next to each other

  21. anonymous
    • one year ago
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    Thank you very much!

  22. anonymous
    • one year ago
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    yw wasn't even that hard was it?

  23. anonymous
    • one year ago
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    no

  24. anonymous
    • one year ago
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    Sorry computer froze again, thank you again @satellite73

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