## anonymous one year ago a. Use a metric ruler to measure the distances between Robinson and Neale on the map. b. Using the scale of the map, find the approximate actual distance by air (not by roads), between Robinson and Neale. c. Approximately how many square miles are shown on this map?

1. anonymous

http://www.intervisualtechnology.us/data/1/12383/texasmap.jpg is the link to the map

2. misssunshinexxoxo

Ok please pull out your ruler and mark it down then post it; I'll go over it

3. misssunshinexxoxo

2.4 centimeters is what you messaged me; what's the mileage

4. misssunshinexxoxo

Looks like 4 miles to me

5. anonymous

Thats the part i'm having trouble with. The scale says 0-5 miles, but idk how to incorporate that with the 2.4 centimeters.

6. misssunshinexxoxo

Is this an essay question?

7. anonymous

no

8. misssunshinexxoxo

I think you separate it

9. anonymous

@jim_thompson5910

10. jim_thompson5910

So you measured the distance between Robinson and Neale and got 2.4 cm?

11. anonymous

yea

12. jim_thompson5910

use a ruler to measure how long the "0-5" bar is

13. anonymous

2.1 cm

14. jim_thompson5910

x = actual distance from Robinson to Neale solve the proportion for x $\Large \frac{\text{Actual Distance}}{\text{Distance on paper}} = \frac{\text{Actual Distance}}{\text{Distance on paper}}$ $\Large \frac{x}{2.4} = \frac{5}{2.1}$ $\Large x = ???$

15. anonymous

5.7

16. anonymous

but it says to find the distance by air and not by roads, what about that part?

17. jim_thompson5910

that's the actual air distance

18. anonymous

and it would be 5.7 for part C also?

19. jim_thompson5910

measure the width and height of the entire map with the ruler

20. jim_thompson5910

what do you get?

21. anonymous

6.8 cm length and width

22. anonymous

so do i just multiply that now?

23. jim_thompson5910

well you first have to convert those distances on paper to actual distances

24. jim_thompson5910

by using a proportion like shown above

25. anonymous

so then 16.19

26. anonymous

i mean 16.19 is the length and width, and multiplying it i get 262.12

27. jim_thompson5910

so you just found that 6.8 cm on paper corresponds to 16.19 miles in actual distance

28. jim_thompson5910

and yeah the approximate actual area is 262.1161 square miles

29. anonymous

yea, i set it up like 5/2.1 = x/6.8 is that right?

30. jim_thompson5910

yes it is

31. anonymous

cool, thank you!

32. jim_thompson5910

no problem