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anonymous

  • one year ago

a. Use a metric ruler to measure the distances between Robinson and Neale on the map. b. Using the scale of the map, find the approximate actual distance by air (not by roads), between Robinson and Neale. c. Approximately how many square miles are shown on this map?

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  1. anonymous
    • one year ago
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    http://www.intervisualtechnology.us/data/1/12383/texasmap.jpg is the link to the map

  2. misssunshinexxoxo
    • one year ago
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    Ok please pull out your ruler and mark it down then post it; I'll go over it

  3. misssunshinexxoxo
    • one year ago
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    2.4 centimeters is what you messaged me; what's the mileage

  4. misssunshinexxoxo
    • one year ago
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    Looks like 4 miles to me

  5. anonymous
    • one year ago
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    Thats the part i'm having trouble with. The scale says 0-5 miles, but idk how to incorporate that with the 2.4 centimeters.

  6. misssunshinexxoxo
    • one year ago
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    Is this an essay question?

  7. anonymous
    • one year ago
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    no

  8. misssunshinexxoxo
    • one year ago
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    I think you separate it

  9. anonymous
    • one year ago
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    @jim_thompson5910

  10. jim_thompson5910
    • one year ago
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    So you measured the distance between Robinson and Neale and got 2.4 cm?

  11. anonymous
    • one year ago
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    yea

  12. jim_thompson5910
    • one year ago
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    use a ruler to measure how long the "0-5" bar is

  13. anonymous
    • one year ago
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    2.1 cm

  14. jim_thompson5910
    • one year ago
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    x = actual distance from Robinson to Neale solve the proportion for x \[\Large \frac{\text{Actual Distance}}{\text{Distance on paper}} = \frac{\text{Actual Distance}}{\text{Distance on paper}}\] \[\Large \frac{x}{2.4} = \frac{5}{2.1}\] \[\Large x = ???\]

  15. anonymous
    • one year ago
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    5.7

  16. anonymous
    • one year ago
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    but it says to find the distance by air and not by roads, what about that part?

  17. jim_thompson5910
    • one year ago
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    that's the actual air distance

  18. anonymous
    • one year ago
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    and it would be 5.7 for part C also?

  19. jim_thompson5910
    • one year ago
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    measure the width and height of the entire map with the ruler

  20. jim_thompson5910
    • one year ago
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    what do you get?

  21. anonymous
    • one year ago
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    6.8 cm length and width

  22. anonymous
    • one year ago
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    so do i just multiply that now?

  23. jim_thompson5910
    • one year ago
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    well you first have to convert those distances on paper to actual distances

  24. jim_thompson5910
    • one year ago
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    by using a proportion like shown above

  25. anonymous
    • one year ago
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    so then 16.19

  26. anonymous
    • one year ago
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    i mean 16.19 is the length and width, and multiplying it i get 262.12

  27. jim_thompson5910
    • one year ago
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    so you just found that 6.8 cm on paper corresponds to 16.19 miles in actual distance

  28. jim_thompson5910
    • one year ago
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    and yeah the approximate actual area is 262.1161 square miles

  29. anonymous
    • one year ago
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    yea, i set it up like 5/2.1 = x/6.8 is that right?

  30. jim_thompson5910
    • one year ago
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    yes it is

  31. anonymous
    • one year ago
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    cool, thank you!

  32. jim_thompson5910
    • one year ago
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    no problem

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