Triangle ABC is congruent to triangle XYZ. Angel A measures 50 degrees. Angle B measures (2x+40) and angle Y (4x+8). Find the value of x.
How do I set this up proportionally?

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The vertices correspond. a-x
b-y
c-z

then you can set angle b = y and solve for x

x = 8? I can't believe I did not see that. It looks so simple now that you've written it...

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