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anonymous
 one year ago
Is relation t a function? Is the inverse of relations t a function?
Relation t
x 0 2 4 6
y 8 7 4 4
anonymous
 one year ago
Is relation t a function? Is the inverse of relations t a function? Relation t x 0 2 4 6 y 8 7 4 4

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0A. Relation t is a function. The inverse of relation t is not a functions. B. Relation t is not a function. The inverse of relation t is a function. C. Relation t is not a function. The inverse of relation t is not a function.

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.2ok so to determine a function we use the vertical line test for a graph. Similarly we use a horizontal line test for a graph to determine a one to one function. but this time we don't have a graph. Instead we have a chart. This may be a while back since I've last did charts though If I remembered correctly the function must have the x not repeating and the one to one function (inverse) must have the y not repeating

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.2yeah... I'm still trying to remember though... this was way back in 2008 when I did this.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Any help is better than no help

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.2ok... now I got my memory back after I read a paragraph somewhere .. we can't have duplicates for x or y

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0So the answer is still A, correct?

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.2there's an example in my book somewhere.. I have to find it before giving out an answer.

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.2ok that was mapping and proofs. It's too strong for this problem... but I do know that we can't have anything repeating

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Im gonna go with A than because the top row isn't repeating

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.2the original function has a repeated value for y though..

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.0Well for it to be a one  to  one function the x and y values are to be used only once. So if you can switch the x and y variables around to create a inverse relation, we would notice function t would not be a one  to  one function since there are two of the same y values, then we can conclude the inverse is not a function.

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.2if we switch.. that would mean that there exists x values that are repeating.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0So it's C @Astrophysics

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.2Ok I'm seeing this horizontally .. I'm going to draw vertical dw:1435810073365:dw

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.2alright so there are repeats.. since we can't have that.. it's not a function .

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.2so switching to grab the inverse dw:1435810139494:dw same problem occurs

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.2Since we have repetitions or duplicates of xvalues with different yvalues, then this relation ceases to be a function.

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.0Well lets put it like this, dw:1435810074921:dw it is not a function since the x value of 4 now has two different y values, so it's not a function, I hope that makes sense

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0So the answer is C correct?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Since if it gets reversed than there would be duplicates on x and y

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.2if it's reversed we have duplicate x values if it's not reversed we have duplicate y values. either way it's not a function since each number has to be unique

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.0Yeah, that sounds good to me, since it's not 1  to  1.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I have another question

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.0Note that for a 1  to  1 function it has to pass both vertical and horizontal line test.

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.2no... 1 to 1 is horizontal line test only

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0What is the inverse of the given function? y = 7x^2  3.

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.2ok first switch the x and y

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.0I just googled it to make sure and look dw:1435810563144:dw

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I wish i was as good at math as you guys are

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.2If no horizontal line intersects the graph of the function more than once, then the function is onetoone.

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.2\[x=7y^23\] k now solve for y

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.2so we need y by itself

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0So how do i factor it to itself?

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.2you want the inverse of the function. This has nothing to do with factoring

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0So how do i do an inverse?

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.0Oh okkkk yes, I understand @UsukiDoll I get what you mean now haha, I kept saying it has to be 1 to 1 for it to pass both, but it just needs to pass horizontal for it to be 1 to 1 and if it passes a vertical line test it is just a function! :) Ok now I'll let you do your thing!

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.2we were on the right track so our original equation y=7x^23 we switch the x and y x=7y^23 now we need to solve for y

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.2to have y by itself we need to ______ 3 to both sides

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0\[y \pm \sqrt{\frac{ 3+x }{ 7}}\]

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.2x+3=7y^2 \[\frac{x+3}{7}=y^2 \rightarrow \sqrt{\frac{x+3}{7}}, \sqrt{\frac{x+3}{7}}\] my x is in a different place but it wouldn't matter since the answer is the same

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0yay we figured it out! *high five*

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0It's a function if we assume \(\{0,2,4,6\}\) is the domain

Hero
 one year ago
Best ResponseYou've already chosen the best response.0For the original question posted, I don't agree with "C" as an answer.

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.0I don't either actually, because I kept saying 1 to 1 function, that is true it's not a 1 to 1 function, but however it is a function as the x does not repeat itself.

Hero
 one year ago
Best ResponseYou've already chosen the best response.0Plot each point, then perform a vertical line test: https://www.desmos.com/calculator/ogb1oqtoi2

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0So i was right when i said it is A?

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.0That seems better

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.0Sorry for the confusion @EllenJaz17 :P

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0No problem, at least im learning

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0A function is: Left total  all elements in the domain used at least once. Many to One  all elements in the domain used no more than once.

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.2thanks for the memory refresher x never had repeats for the function , but switch x and y and now there are repeats

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Mono, did you draw that avatar?

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.2yeah it was A for that question

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.2but like I said I've done this way back . so it's not 100% until @wio showed up and I saw what he was talking about.

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.2then it popped back into my mind... there's a bunch of Math topics that don't appear any more when you study further

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.0Yeah it was a good review, I think last time I did a problem like this was in middle school

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.2the graph versions.. those were the ones I knew and functions... well my book had a strong approach to it... it was about mapping... surjection/injection bijection so I highly doubt it would be used.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0For the function f(x) = (82x)2 ,find f1 . Determine whether f1 is a function.
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