anonymous
  • anonymous
A teacher promised a movie day to the class that did better, on average, on their test. The box plot shows the results of the test: The 2nd period class should get the reward. They have the highest score, a perfect 100. The 2nd period class should get the reward. They have a higher median. The 4th period class should get the reward. Though the medians are the same, the first and third quartiles are higher, so the students did better on average than in the 2nd period class. The 4th period class should get the reward. Their lowest score is and should be thrown out
Mathematics
chestercat
  • chestercat
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anonymous
  • anonymous
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jennyrlz
  • jennyrlz
Well we are looking for which class as a accumulative force did better
jennyrlz
  • jennyrlz
Meaning the it is not a

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anonymous
  • anonymous
ok, so D isnt it either, because it says to throw out an outlier
jennyrlz
  • jennyrlz
Since we see that over all the second period class is overall ahead in the picture, leaving only one option :)
jennyrlz
  • jennyrlz
Yup ^.^
jennyrlz
  • jennyrlz
Meaning b and c, b is the answer because they do have the highest median :)
anonymous
  • anonymous
ok, thank you :)
jennyrlz
  • jennyrlz
They could have used the word mean (average) and it would've still been b
jennyrlz
  • jennyrlz
No :)
jennyrlz
  • jennyrlz
Np*
jennyrlz
  • jennyrlz
Auto correct xD
anonymous
  • anonymous
no, it would be C, because if its based on average, 4th period's q1 and q3 are higher than second's
anonymous
  • anonymous
and the medians are the same
jennyrlz
  • jennyrlz
Wait but... Well... I see... My bad :/
jennyrlz
  • jennyrlz
But hey I am glad you found the answer
jennyrlz
  • jennyrlz
I'll medal you :)
anonymous
  • anonymous
thanks for the help
jennyrlz
  • jennyrlz
Np, wish I could've been of more use :/
anonymous
  • anonymous
its fine

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