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anonymous
 one year ago
For the function f(x) = (82x)2 ,find f1 . Determine whether f1 is a function.
anonymous
 one year ago
For the function f(x) = (82x)2 ,find f1 . Determine whether f1 is a function.

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campbell_st
 one year ago
Best ResponseYou've already chosen the best response.0just start by swapping x and y so the original equation is \[y = (8  2x)^2\] do the swap \[x = (8  2y)^2\] now may y the subject of the equation

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0So should i solve for x? @campbell_st

campbell_st
 one year ago
Best ResponseYou've already chosen the best response.0no you should solve for y... 1st step is to take the square root of both sides of the equation...

campbell_st
 one year ago
Best ResponseYou've already chosen the best response.0well the problem is that the original equation is a function, the inverse will be a relationship... and your solution seems ok...

campbell_st
 one year ago
Best ResponseYou've already chosen the best response.0the way you test the inverse is a function is to use the vertical line test after graphing the curve

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0It doesnt match any of my answers

campbell_st
 one year ago
Best ResponseYou've already chosen the best response.0so do you have \[f^{1}(x) = \frac{8  \sqrt{x}}{2}\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0idk i cant see my answer A lol it's probably that one than

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0All my other answers are a + not a  and I cant see answer A

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.1take the one with the + ? Idk.. but @campbell_st is right. you switch the signs of x and y and solve for y

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Is the final answer correct? If so I'll just chose A because everything else is a + after the 8

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.1?!!!! ok looks like I have to square root both sides or I won't go further lol

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0haha I just want to make sure the answer is correct

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.1\[x = (8  2y)^2\] [square both sides so we have y by itself] \[\sqrt{x}=82y\] ok so I'm just gonna stop at this point. I don't want to get busted :P but anyway we need y by itself so I ____________ 8 from both sides

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.1yes \[\sqrt{x}8=2y\] so now what do we need to do to get y by itself?

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.1not quite. We can't use addition... try again

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.1yes we divide 2 on both sides.

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.1\[\frac{\sqrt{x}8}{2}=y\] we can simplify further

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.1for starters we can split this equation up.... \[\frac{\sqrt{x}8}{2}=y \rightarrow \frac{\sqrt{x}}{2}+\frac{8}{2}\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0So his answer was right than

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.1a negative divided by a negative turns positive

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.1yeah.. and about his answer..I think he dropped the negative sign

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.1\[\frac{\sqrt{x}}{2}+4\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0ok this is my final question tonight lol

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0For the function f(x) = x2  12, find (f o f1)(4)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0do we put 4 in all the x's?

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.1hmmmm looks like we need to find f^{1} first and plug that guy into f(x)

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.1\[f(x) =x^212\] f(x) is also y \[y=x^212 \] now how do we find the inverse ?

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.1that's the second step what is the first step? what needs to be switched?

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.1yes now we solve for y \[x=y^212\]

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.1so how do we get y by itself? we need to __________ 12 to both sides

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.1\[x+12=y^2 \] good now we need to ___________ both sides we need a y by itself... it can't have an exponent

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.1no. umm.. what is the square root of y^2 ?

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.1it can't be nothing.. otherwise we won't have y ._.

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.1maybe exponential form will be easier \[\large y^\frac{2}{2}\] what's 2/2 ?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0it would just turn into y

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.1yes but keep in mind since we took the square root of y^2 we have to take the square root of the left hand side as well \[\sqrt{x+12}=y\]

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.1eep \[f^{1}(x) = \sqrt{x+12} \]

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.1now we will place that inverse function into our \[f(x) = x^212 \] but something unusual is going to happen

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.1oh wait it won't sorry we will still have something ok good whew

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.1so f o f^{1} means place f^{1} inside the f(x) function.. yeah I was just looking at the number and not the variable xD

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.1no try placing f inverse in f(x)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0im gonna need for you to be online whenever i am online lol

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.1\[f^{1}(x) = \sqrt{x+12} , f(x) = x^212 \] \[f(x) \cdot f^{1}(x) \] \[f^{1}(x) \cdot f(x) = (\sqrt{x+12})^212 \] \[f^{1}(x) \cdot f(x) = x+1212 \] \[f^{1}(x) \cdot f(x) =x \] when x = 4 \[f^{1}(x) \cdot f(x) =4 \]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Thank you for all of your help, I got an A on my hw

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.1oh that's awesome! :D
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