anonymous
  • anonymous
Find the maximum or minimum of the following quadratic function: y = -2x2 + 4x - 1. -1 0 1 4
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
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anonymous
  • anonymous
please help...
campbell_st
  • campbell_st
is this question algebra of calculus...?
campbell_st
  • campbell_st
ok... here is the the key, the parabola is concave down, since the coefficient of x^2 is -2 so for a quadratic \[ax^2 + bx + c = 0\] the line of symmetry is \[x = \frac{-b}{2 \times a}\] you have a = -2 and b = 4 the maximum of minimum lies on the line of symmetry so find the value of x, and then substitute it into the original equation to find the max value

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anonymous
  • anonymous
I don't quite understand... I just need to know whether its a b c or d im learning how to do it I just don't have the time...
campbell_st
  • campbell_st
yes but to find it, a simple method is to find the line of symmetry and the substitute that value into the equation
campbell_st
  • campbell_st
and alternate method is to just graph the curve and read off the value.
anonymous
  • anonymous
look im not like most people on here I know nearly nothing about math which is why im taking this class.. I don't have any idea what youre talking about and im stressing about this cause I need to pass...
campbell_st
  • campbell_st
ok... then use this site https://www.desmos.com/calculator type in the equation on the left and then read off the highest y value
anonymous
  • anonymous
1?...
campbell_st
  • campbell_st
that correct.... the line of symmetry is x = -4/(2 x -2) so x = 1 subsitute that value into the equation and you get y = -2 *(1)^2 + 4*(1) - 1 or y = 1 so the parabola is concave down, the you have a maximum at y = 1
anonymous
  • anonymous
so one is the answer?
campbell_st
  • campbell_st
that's correct

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