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anonymous
 one year ago
In a party every person shakes hand with every other person. If there was a total 105 handshakes in the party. Find the number of people present who were present in the party?
anonymous
 one year ago
In a party every person shakes hand with every other person. If there was a total 105 handshakes in the party. Find the number of people present who were present in the party?

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ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.2Say there are \(n\) people in the room. The first person may shake hands with \(n1\) other people. The next person may shake hand with \(n2\) other people, not counting the first person again. ... Adding them up gives \[(n1)+(n2)+\cdots+3+2+1\] which is same as the sum of first \(n1\) natural numbers.

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.2That means we end up solving a quadratic equation \[\dfrac{n(n1)}{2} = 105\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0i have also got another method,simply we will apply combination NC2 \[N!/2 !(N2) !=105\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0anyhow thanks for the help!

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.2Yes I like your method
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