anonymous
  • anonymous
What is the general form of the equation for the given circle? x2 + y2 − 8x − 8y + 23 = 0 x2 + y2 − 8x − 8y + 32 = 0 x2 + y2 − 4x − 4y + 23 = 0 x2 + y2 + 4x + 4y + 9 = 0
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
idk how to put a pic on here so im just gonna describe the circle
anonymous
  • anonymous
it's 90 degrees with points A (4,7) and B (7,4)
anonymous
  • anonymous
please help!

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anonymous
  • anonymous
@Marcorie
anonymous
  • anonymous
A) (x-4)^2 + (y-4)^2 = 3
anonymous
  • anonymous
do i solve that or something?
anonymous
  • anonymous
No i solved the first equation this is standard form for a circle
anonymous
  • anonymous
(x-h)^2 + (y-h)^2 = r^2
xapproachesinfinity
  • xapproachesinfinity
you have to show how ? no direct answer are allowed in OP
anonymous
  • anonymous
Okay sorry I'm new to this
anonymous
  • anonymous
i dont have to show how i just need the answer @xapproachesinfinity
anonymous
  • anonymous
(x-h)^2 + (y-h)^2 = r^2
anonymous
  • anonymous
it's fine i just really need the answer @Deezzz
xapproachesinfinity
  • xapproachesinfinity
it is not allowed in open study!!
anonymous
  • anonymous
where (h,k) is the center and r is the radius of the circle
anonymous
  • anonymous
please just help!! i honestly dont care about the work i just really need the answer so i could pass this damn test
xapproachesinfinity
  • xapproachesinfinity
whether you just need the answer or not you have the follow the guide lines
anonymous
  • anonymous
-.- @xapproachesinfinity
anonymous
  • anonymous
|dw:1435852626836:dw|
anonymous
  • anonymous
that's all that is given to me
anonymous
  • anonymous
it's 90 degrees though
anonymous
  • anonymous
1) (x-4)^2 + (y-4)^2 = 3
anonymous
  • anonymous
its the first one
anonymous
  • anonymous
where your center is 4,4 and radius of 3
anonymous
  • anonymous
are u sure?
anonymous
  • anonymous
Positive
anonymous
  • anonymous
ok imma choose it
anonymous
  • anonymous
it was correct! thank you!
anonymous
  • anonymous
Welcome

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