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anonymous
 one year ago
What is the standard form of the equation of a circle with its center at (2, 3) and passing through the point (2, 0)?
(x − 2)squared + (y + 3)squared = 5
(x + 2)squared + (y − 3)squared = 25
(x − 2)squared + (y + 3)squared = 25
(x − 2)squared − (y + 3)squared = 5
anonymous
 one year ago
What is the standard form of the equation of a circle with its center at (2, 3) and passing through the point (2, 0)? (x − 2)squared + (y + 3)squared = 5 (x + 2)squared + (y − 3)squared = 25 (x − 2)squared + (y + 3)squared = 25 (x − 2)squared − (y + 3)squared = 5

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welshfella
 one year ago
Best ResponseYou've already chosen the best response.2the general form is (x  a)^" + (y  b)^2 = r^2 where (a,b) is the center and r is the radius

welshfella
 one year ago
Best ResponseYou've already chosen the best response.2so you should be able to work out the left side now by plugging in a = 2 and b = 3

welshfella
 one year ago
Best ResponseYou've already chosen the best response.2and the radius will be the distance between the center and the point (2,0)

welshfella
 one year ago
Best ResponseYou've already chosen the best response.2yw  if you need more help let me know

Hero
 one year ago
Best ResponseYou've already chosen the best response.0In general, the standard form of the equation of a circle is \((x  h)^2 + (y  k)^2 = r^2\). In this case, (h,k) = (2,3) and (x,y) = (2,0). Plug both points in to the equation, then simplify and solve for r. Next rewrite the standard form of the equation, except this time, insert the given center point and the value of r.
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