anonymous
  • anonymous
What is the standard form of the equation of a circle with its center at (2, -3) and passing through the point (-2, 0)? (x − 2)squared + (y + 3)squared = 5 (x + 2)squared + (y − 3)squared = 25 (x − 2)squared + (y + 3)squared = 25 (x − 2)squared − (y + 3)squared = 5
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
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anonymous
  • anonymous
@Deezzz
anonymous
  • anonymous
@welshfella
anonymous
  • anonymous
@rvc

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welshfella
  • welshfella
the general form is (x - a)^" + (y - b)^2 = r^2 where (a,b) is the center and r is the radius
anonymous
  • anonymous
yes
welshfella
  • welshfella
so you should be able to work out the left side now by plugging in a = 2 and b = -3
welshfella
  • welshfella
and the radius will be the distance between the center and the point (-2,0)
anonymous
  • anonymous
thanks
welshfella
  • welshfella
yw - if you need more help let me know
rvc
  • rvc
:) all the best
anonymous
  • anonymous
@Deezzz
anonymous
  • anonymous
@nincompoop
anonymous
  • anonymous
@Hero
anonymous
  • anonymous
@triciaal
Hero
  • Hero
In general, the standard form of the equation of a circle is \((x - h)^2 + (y - k)^2 = r^2\). In this case, (h,k) = (2,3) and (x,y) = (-2,0). Plug both points in to the equation, then simplify and solve for r. Next re-write the standard form of the equation, except this time, insert the given center point and the value of r.
anonymous
  • anonymous
ok ill try, thanks

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