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anonymous
 one year ago
MEDAL!!
Given f(x) = 5x − 7 and g(x) = 11x − 1, solve for (f + g)(x) and select the correct answer below.
(f + g)(x) = 16x − 6
(f + g)(x) = 16x + 8
(f + g)(x) = 16x − 8
(f + g)(x) = 6x − 6
anonymous
 one year ago
MEDAL!! Given f(x) = 5x − 7 and g(x) = 11x − 1, solve for (f + g)(x) and select the correct answer below. (f + g)(x) = 16x − 6 (f + g)(x) = 16x + 8 (f + g)(x) = 16x − 8 (f + g)(x) = 6x − 6

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Which one makes more sense? I'm clueless

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Really your just taking the two equations and combining them.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I would say C but I'm really rusty on this type of stuff.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I was thinking the same, do you think you could help me with two more?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0If (9x − 4)(9x + 4) = ax2 − b, what is the value of a? The value of a is _____________. Numerical Answers Expected! Answer for Blank 1:

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0"Numerical Answers Expected!" Darn...I thought it was llama...

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Lol same, i guess they mean take the answer and put it into a numerical answer

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0A = 81 Taken from: http://www.wolframalpha.com/input/?i=%289x+%E2%88%92+4%29%289x+%2B+4%29+%3D+ax2+%E2%88%92+b

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Consider the functions f(x) = x2 − 13 and g(x) = x + 5. What is the value of f[g(−4)]? −12 3 −13 8

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0This one is pinching me.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Alright man thanks for the help!!

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0ANy time m8! Sorry I couldn't help all the way!
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