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\[\frac{ 5x ^{2}+65x+60 }{ x ^{2}+10x-24 }=\frac{ 5x+5 }{ x-2 }\] then which of the following are possible values of x? -60 -12 -1 1 2 5
what do u think
i have x+1=x+1

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Other answers:

the given equation satisfies all real values except \(x=2,-12\) as we have in denominators \((x-12)(x-2)\) which would make equation undefined
wait what?
i thought it worked out for all of them
it satisfies all values except \(x=2\) and \(x=-12\)
can u explain why?
because in the denominator u have \(x^2+10x-24=(x+12)(x-2)\) if u put \(x=2\) or \(x=-12\) the denominator will become zero and any number divide by zero is undefined.
ohhhh ic
is there an easier way to check the answer?
yes there is Set the denominator equal to zero and solve $$ x^2+10x-24=(x+12)(x-2)=0 $$ This helps you find values that x should NOT be Just be careful. Before you do this, just make sure that none of these terms is cancelled by the numerator.
You never want the denominator equal to zero.

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