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anonymous

  • one year ago

Please help me =*(

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  1. anonymous
    • one year ago
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    \[\frac{ 5x ^{2}+65x+60 }{ x ^{2}+10x-24 }=\frac{ 5x+5 }{ x-2 }\] then which of the following are possible values of x? -60 -12 -1 1 2 5

  2. anonymous
    • one year ago
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    what do u think

  3. anonymous
    • one year ago
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    i have x+1=x+1

  4. mathmath333
    • one year ago
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    the given equation satisfies all real values except \(x=2,-12\) as we have in denominators \((x-12)(x-2)\) which would make equation undefined

  5. anonymous
    • one year ago
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    wait what?

  6. anonymous
    • one year ago
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    i thought it worked out for all of them

  7. mathmath333
    • one year ago
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    it satisfies all values except \(x=2\) and \(x=-12\)

  8. anonymous
    • one year ago
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    can u explain why?

  9. mathmath333
    • one year ago
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    because in the denominator u have \(x^2+10x-24=(x+12)(x-2)\) if u put \(x=2\) or \(x=-12\) the denominator will become zero and any number divide by zero is undefined.

  10. anonymous
    • one year ago
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    ohhhh ic

  11. anonymous
    • one year ago
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    is there an easier way to check the answer?

  12. ybarrap
    • one year ago
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    yes there is Set the denominator equal to zero and solve $$ x^2+10x-24=(x+12)(x-2)=0 $$ This helps you find values that x should NOT be Just be careful. Before you do this, just make sure that none of these terms is cancelled by the numerator.

  13. ybarrap
    • one year ago
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    You never want the denominator equal to zero.

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