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anonymous

  • one year ago

MEDAL! Please explain clearly, step by step how to do this! Solve for x. 5a/x = 5b/x-1

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  1. pooja195
    • one year ago
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    \[\huge~\rm~\frac{ 5a }{ x}=\frac{ 5b }{ x-1}\]

  2. pooja195
    • one year ago
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    like that?

  3. anonymous
    • one year ago
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    @pooja195 Yeah! :)

  4. pooja195
    • one year ago
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    Do you know where to start? :)

  5. anonymous
    • one year ago
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    Don't I cross multiply?

  6. pooja195
    • one year ago
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    yes! :) set uo the equation u get once you do that

  7. anonymous
    • one year ago
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    5a(x-1) = 5b(x) Is this right so far? Or am I way off...?

  8. pooja195
    • one year ago
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    good continue

  9. anonymous
    • one year ago
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    Whats the next step?

  10. pooja195
    • one year ago
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    5a(x-1) distribute

  11. anonymous
    • one year ago
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    How do I do that? I'm sorry I just suck at math... Every other subject are A's! XD

  12. pooja195
    • one year ago
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    \[\huge~\rm~5a~\times~x=?\] \[\huge~\rm~5\times-1=? \]

  13. anonymous
    • one year ago
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    5ax and 4x?

  14. pooja195
    • one year ago
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    we are multiplying so it would be -5 5ax−5a=5bx

  15. pooja195
    • one year ago
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    what do u do from here?

  16. pooja195
    • one year ago
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    need help ?

  17. anonymous
    • one year ago
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    Yes please

  18. pooja195
    • one year ago
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    hmm :/ im not sure where to go from here maybe @mLe can help ;-; ?

  19. mLe
    • one year ago
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    get all the terms that have x in it alone to one side

  20. mLe
    • one year ago
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    subtract 5bx from both sides

  21. mLe
    • one year ago
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    and add 5a to both sides

  22. mLe
    • one year ago
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    then move the x out to the front ... opposite of distributing... for example if I had 7xy + 9xz I would get x (7y + 9z) then divide both sides by the stuff in the parenthesis to get it alone

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