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mathmath333

  • one year ago

solve for \(x\).

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  1. mathmath333
    • one year ago
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    \(\large \color{black}{\begin{align} \sqrt{x^2}<x+1\hspace{.33em}\\~\\ \end{align}}\)

  2. anonymous
    • one year ago
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    Need help @mathmath333 ^.^

  3. anonymous
    • one year ago
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    If you think im new and dont know much about OS this is my alt account .-. my original is @just_one_last_goodbye

  4. anonymous
    • one year ago
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    Let's take a look... ^_^

  5. anonymous
    • one year ago
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    but @mathmath333 I'm being monitored by mods and cant give a direct answer so please stay I need your participation

  6. anonymous
    • one year ago
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    First we need to find the "real region" of the problem

  7. anonymous
    • one year ago
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    \[\sqrt{x ^{2}}\] is real to what?

  8. anonymous
    • one year ago
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    @mathmath333 u there?

  9. anonymous
    • one year ago
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    what have you got math?

  10. mathmath333
    • one year ago
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    i have got \(x>-1/2\) and \(x>0\)

  11. anonymous
    • one year ago
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    It is real to \[(x ^{2}) \ge 0\]

  12. anonymous
    • one year ago
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    @mathmath333 thats the answer x > -1/2 is the solution

  13. anonymous
    • one year ago
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    x>-1/2 covers x>0 also, so answer is x>-1/2

  14. anonymous
    • one year ago
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    \[[Solution: x > -\frac{ 1 }{ 2 }\] \[[Decimal: x > -0.5]\] \[[Interval Notation: (-\frac{ 1 }{ 2 }, \infty) ]\]

  15. anonymous
    • one year ago
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    Oh hey @wio huge fan of your extension that you made for OS ^.^ im currently using all of them

  16. mathmath333
    • one year ago
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    but the common region between \(x>0.5\) and \(x>0\) so why not \(x>0\)

  17. anonymous
    • one year ago
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    x>-0.5 not x>0.5

  18. mathmath333
    • one year ago
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    yea i mean \(x>-0.5\)

  19. anonymous
    • one year ago
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    You can split it up: \[ x\lt x+1 \\ -x\lt x+1 \]The first equation will be true for all real \(x\), and so only the second equation matters. That equation leads to: \[ 0\lt 2x+1 \implies -\frac 12 \lt x \]

  20. dan815
    • one year ago
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    |dw:1435865650234:dw|

  21. anonymous
    • one year ago
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    @Captain_America_Army Glad you like it.

  22. dan815
    • one year ago
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    sqrt(x^2) is another way to write the abs value of x

  23. dan815
    • one year ago
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    |dw:1435865730882:dw|

  24. mathmath333
    • one year ago
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    how do u draw that

  25. dan815
    • one year ago
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    draw the y=ABS(x) and the line y=x+1

  26. dan815
    • one year ago
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    like wio mentioned abs(x) can be split into 2 lines -x and x

  27. mathmath333
    • one year ago
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    ok thnx every one

  28. anonymous
    • one year ago
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    Where did the \(0\lt x\) come from?

  29. anonymous
    • one year ago
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    That was a good question math, why x>-0.5 and not x>0

  30. mathmath333
    • one year ago
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    but desmos did this https://www.desmos.com/calculator/lnftaoee2g

  31. dan815
    • one year ago
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    my drawing is so bad actually lol

  32. dan815
    • one year ago
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    they are parallel lines they wont intersect

  33. dan815
    • one year ago
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    but u get the point

  34. mathmath333
    • one year ago
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    \(\sqrt{x^2}\implies x>0 ,\ \ and \ \ x<0\)

  35. anonymous
    • one year ago
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    In my equations, the first one assumes \(0\lt x\) and finds out \(x\in (0, \infty)\). The second one assumes \(x\lt 0\) and finds out \(x\in (-0.5, 0)\).

  36. dan815
    • one year ago
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    |dw:1435866160067:dw|

  37. anonymous
    • one year ago
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    We union these intervals (because absolute value splitting up of problems is a union). We also check that \(x=0\) works. So our result is \(x\in (-0.5, \infty)\).

  38. anonymous
    • one year ago
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    thanks wio

  39. anonymous
    • one year ago
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    o.o working in the middle of OS math legends.... ~honored~

  40. dan815
    • one year ago
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    |dw:1435866195634:dw|

  41. mathmath333
    • one year ago
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    i get confused where to choose common region \(\cap\) and where to choose union region \(\cup\)

  42. mathmath333
    • one year ago
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    in math questions haha

  43. anonymous
    • one year ago
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    ^ agreed

  44. dan815
    • one year ago
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    i remember when you see a U its union

  45. dan815
    • one year ago
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    and upsinde down U looks kind of like n for n-tersect

  46. dan815
    • one year ago
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    u n

  47. anonymous
    • one year ago
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    looks like a man with no hair to me .-.

  48. dan815
    • one year ago
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    it actually is n flipped in this font

  49. dan815
    • one year ago
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    180 deg rotation

  50. mathmath333
    • one year ago
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    dan i got this https://www.desmos.com/calculator/vlaerg67rk

  51. dan815
    • one year ago
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    yep

  52. anonymous
    • one year ago
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    Dear math, please stop asking us to find your \(x\), he is gone and he's never coming back. just accept it. xD

  53. anonymous
    • one year ago
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    ~face palm~ smh >.< "math jokes"

  54. mathmath333
    • one year ago
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    no he is back

  55. dan815
    • one year ago
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    shes gonna eat \[\pi \] and get fat now

  56. anonymous
    • one year ago
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    what u gotta say to that Muk xD

  57. anonymous
    • one year ago
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  58. anonymous
    • one year ago
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    I am also going to eat a\[\pi z^2 a\]

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  59. anonymous
    • one year ago
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    ~yawn~ so instead of helping people... we are here making math jokes... that are more dry than the desert? nice ladies just nice.... http://www.joesdaily.com/wp-content/uploads/2014/11/joker-clapping.gif

  60. anonymous
    • one year ago
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    :)) xD

  61. anonymous
    • one year ago
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    .-. Hey Sexy Lady ~points @mukushla ~ Opa Opa Opa Gangnam style

  62. mathmath333
    • one year ago
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    |dw:1435867862718:dw|

  63. anonymous
    • one year ago
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    .o. @mathmath333 show me how to do that ;-; I've asked everyone and they dont want to show me

  64. anonymous
    • one year ago
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    That mod "TkHunny" =.= banned me for a week for posting external links

  65. anonymous
    • one year ago
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    will 10 owl bucks do the job?

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