anonymous
  • anonymous
how to write y= 2x^2 + 8x +7 in standard (vertex) form
Mathematics
jamiebookeater
  • jamiebookeater
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NathalyN
  • NathalyN
= 2x^2 + 8x + 7 = 2(x^2+4x) +7 = 2(x^2 +4 +4) + 7 -8 = 2(x+2)^2 -1 Therefore vertex is (-2,-1)....................................
campbell_st
  • campbell_st
well 1 version of standard vertex form is \[y = a(x -h)^2 + k\] so group the terms in x \[y = (2x^2 + 8x) + 7\] remove the common factor for the terms in x \[y = 2(x^2 + 4x) + 7\] now complete the square in x, does that make sense?
campbell_st
  • campbell_st
there you go... someone has given you the answer

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