A scientist is studying the growth of a particular species of plant. He writes the following equation to show the height of the plant f(n), in cm, after n days: f(n) = 12(1.03)n Part A: When the scientist concluded his study, the height of the plant was approximately 16.13 cm. What is a reasonable domain to plot the growth function? (4 points) Part B: What does the y-intercept of the graph of the function f(n) represent? (2 points) Part C: What is the average rate of change of the function f(n) from n = 3 to n = 10, and what does it represent? (4 points

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A scientist is studying the growth of a particular species of plant. He writes the following equation to show the height of the plant f(n), in cm, after n days: f(n) = 12(1.03)n Part A: When the scientist concluded his study, the height of the plant was approximately 16.13 cm. What is a reasonable domain to plot the growth function? (4 points) Part B: What does the y-intercept of the graph of the function f(n) represent? (2 points) Part C: What is the average rate of change of the function f(n) from n = 3 to n = 10, and what does it represent? (4 points

Mathematics
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hey im here
you are missing exponents on this equation f(n) = 12(1.03)n

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Other answers:

What do you mean?
i think your equation is wrong
it is correctly wrriten
are you absolutely sure, because, they do not ask growth rate for non exponential equations
f(n) = 12(1.03)^n
attaboy
(:
mhm
Ok so what is next?
now lets do part A what height did the plant end at
16.13cm
16.13 = 12(1.03)^n so we have find out what day this was
this will tell us approximately how high you want to make our domain on the n axis
|dw:1435869005066:dw|
so we are checking the last day he did his study upto
16.13 = 12(1.03)^n okay so what can we do to solve this equation
for n
\[16.13 = 12(1.03)^n \]
@samkellogg help plz
well so how about starting by dividing both sides by 12
which question?
what sides are you talking about @dan815
hello do u need help on all of them or just one?
All but can we do part a now
yes I was just wondering
ok so whats first?
okay sorry my computer is bing really stuped so hold on
ok thats fine
1.3

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