chris215
  • chris215
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Physics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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chris215
  • chris215
2 m/s, -3m/s -3 m/s, 2 m/s 2 m/s, 3m/s -2 m/s, -3 m/s
Michele_Laino
  • Michele_Laino
here you have to apply the total momentum conservation law, furthermore, since the collision is elastic, you can apply the kinetic energy conservation law
Michele_Laino
  • Michele_Laino
so we can write the subsequent equations: \[\Large \left\{ \begin{gathered} m{\mathbf{u}} + m{\mathbf{v}} = m{\mathbf{u'}} + m{\mathbf{v'}} \hfill \\ \frac{1}{2}m{u^2} + \frac{1}{2}m{v^2} = \frac{1}{2}mu{'^2} + \frac{1}{2}mv{'^2} \hfill \\ \end{gathered} \right.\] where u, v are the initial velocities, namely before collision of the two balls, and u', v' are the corresponding velocities after collision. Furthermore m is the common mass of the two balls. Please note that the first equation is a vector equation. you can use this subsequent reference system: |dw:1435934610110:dw|

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