A community for students.

Here's the question you clicked on:

55 members online
  • 0 replying
  • 0 viewing

anonymous

  • one year ago

Use basic identities to simplify the expression. cosecant of theta times cotangent of theta divided by secant of theta.

  • This Question is Closed
  1. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    write everything in terms of sine and cosine and see what cancels

  2. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    \( \huge \frac{\csc \theta \times \cot \theta}{\sec \theta} \) This is what we are working with correct?

  3. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    These things can get tricky but they are fun, when you are not being timed to do them lol

  4. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    Haha yeah and that is what the question is :)

  5. DecentNabeel
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    @Nixy cot=cos/sin not sin/cos

  6. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    opps yep thanks for the catch

  7. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    \( \huge \frac{\frac{1}{\sin \theta} \times \frac{cos}{sin}}{\sec \theta} \) now work the top

  8. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    Uhhh this is bad, I don't know how to....sorry I am taking this online and my teacher isn't that helpful :(

  9. DecentNabeel
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    \[\mathrm{Simplify}\:\frac{\frac{1}{\sin \left(θ\right)}\cdot \frac{\sin \left(θ\right)}{\cos \left(θ\right)}}{\sec \left(θ\right)}:\quad 1\]

  10. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    wait isn't it cos over sin?

  11. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    Yes, he made a boo boo too :-D

  12. DecentNabeel
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    yes

  13. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    sec is 1/cos theta correct? so would I put that in?

  14. DecentNabeel
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    yes

  15. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    and then cancel out the cos?

  16. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    @peachpi chime in any time to help :-) @peachpi is good at these. She/He has helped me on some before.

  17. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    Oh okay thanks :)

  18. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    you guys look like you have it under control

  19. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    write the denominator as 1/cos Θ. then flip it to the reciprocal when you change division to multiplication |dw:1435872610978:dw|

  20. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    nothing cancels but you can multiply straight across

  21. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    so it comes out to cot theta ^2?

  22. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    yes

  23. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    oh wow so I made it more complicated than it was

  24. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    yeah that happens a lot with these. I've done one on here where I basically went around in circles twice before getting to the solution

  25. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    Haha yeah oops my bad... anyways thank you so much to all of you!! I'll remember your usernames for sure because I'm sure I'll need help later on :)

  26. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    I think I made a boo boo

  27. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    yeah somewhere between the 5th and 6th steps

  28. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    @peachpi

  29. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    Nope still wrong... lol

  30. LynFran
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 1

    how about \[\frac{ 1 }{ \sin \theta }*\frac{ \cos \Theta }{ \sin \Theta }/\sec\]\[\frac{ \cos \theta }{ \sin ^{2}\theta }*\cos\]\[\frac{ \cos ^{2}\theta }{ \sin ^{2}\theta } \]\[\cot ^{2}\theta \]

  31. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    @LynFran is correct. @Nixy It looked like you were cancelling/dividing one part of the numerator but not the other

  32. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    I got what LynFran got

  33. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    \[ \huge \frac{\frac{1-sin^2}{sin^2 }}{1} \] \[ \huge \frac{\frac{cos^2}{sin^2 }}{1} \]

  34. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    yeah that's it

  35. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    \[ \huge \frac{\frac{1}{\sin \theta} \times \frac{cos}{sin}}{\sec \theta} \] \[ \huge \frac{\frac{cos}{\sin^2}}{\sec \theta} \] \[ \huge \frac{\frac{cos}{\sin^2}}{\frac{1}{cos}} \] \[ \huge \frac{\frac{cos}{\sin^2}}{\frac{1}{cos}} \times cos \] \[ \huge \frac{\frac{cos^2}{\sin^2}}{\frac{1}{cos}} \times cos \] \[ \huge \frac{\frac{cos^2}{\sin^2}}{1} \] \[ \huge \frac{cos^2}{sin^2} \] \[ \huge \cot^2 \]

  36. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    These things are fun :-D

  37. Not the answer you are looking for?
    Search for more explanations.

    • Attachments:

Ask your own question

Sign Up
Find more explanations on OpenStudy
Privacy Policy

Your question is ready. Sign up for free to start getting answers.

spraguer (Moderator)
5 → View Detailed Profile

is replying to Can someone tell me what button the professor is hitting...

23

  • Teamwork 19 Teammate
  • Problem Solving 19 Hero
  • You have blocked this person.
  • ✔ You're a fan Checking fan status...

Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.

This is the testimonial you wrote.
You haven't written a testimonial for Owlfred.