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anonymous
 one year ago
Use basic identities to simplify the expression.
cosecant of theta times cotangent of theta divided by secant of theta.
anonymous
 one year ago
Use basic identities to simplify the expression. cosecant of theta times cotangent of theta divided by secant of theta.

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0write everything in terms of sine and cosine and see what cancels

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0\( \huge \frac{\csc \theta \times \cot \theta}{\sec \theta} \) This is what we are working with correct?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0These things can get tricky but they are fun, when you are not being timed to do them lol

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Haha yeah and that is what the question is :)

DecentNabeel
 one year ago
Best ResponseYou've already chosen the best response.0@Nixy cot=cos/sin not sin/cos

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0opps yep thanks for the catch

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0\( \huge \frac{\frac{1}{\sin \theta} \times \frac{cos}{sin}}{\sec \theta} \) now work the top

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Uhhh this is bad, I don't know how to....sorry I am taking this online and my teacher isn't that helpful :(

DecentNabeel
 one year ago
Best ResponseYou've already chosen the best response.0\[\mathrm{Simplify}\:\frac{\frac{1}{\sin \left(θ\right)}\cdot \frac{\sin \left(θ\right)}{\cos \left(θ\right)}}{\sec \left(θ\right)}:\quad 1\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0wait isn't it cos over sin?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Yes, he made a boo boo too :D

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0sec is 1/cos theta correct? so would I put that in?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0and then cancel out the cos?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0@peachpi chime in any time to help :) @peachpi is good at these. She/He has helped me on some before.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0you guys look like you have it under control

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0write the denominator as 1/cos Θ. then flip it to the reciprocal when you change division to multiplication dw:1435872610978:dw

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0nothing cancels but you can multiply straight across

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0so it comes out to cot theta ^2?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0oh wow so I made it more complicated than it was

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0yeah that happens a lot with these. I've done one on here where I basically went around in circles twice before getting to the solution

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Haha yeah oops my bad... anyways thank you so much to all of you!! I'll remember your usernames for sure because I'm sure I'll need help later on :)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I think I made a boo boo

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0yeah somewhere between the 5th and 6th steps

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Nope still wrong... lol

LynFran
 one year ago
Best ResponseYou've already chosen the best response.1how about \[\frac{ 1 }{ \sin \theta }*\frac{ \cos \Theta }{ \sin \Theta }/\sec\]\[\frac{ \cos \theta }{ \sin ^{2}\theta }*\cos\]\[\frac{ \cos ^{2}\theta }{ \sin ^{2}\theta } \]\[\cot ^{2}\theta \]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0@LynFran is correct. @Nixy It looked like you were cancelling/dividing one part of the numerator but not the other

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I got what LynFran got

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0\[ \huge \frac{\frac{1sin^2}{sin^2 }}{1} \] \[ \huge \frac{\frac{cos^2}{sin^2 }}{1} \]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0\[ \huge \frac{\frac{1}{\sin \theta} \times \frac{cos}{sin}}{\sec \theta} \] \[ \huge \frac{\frac{cos}{\sin^2}}{\sec \theta} \] \[ \huge \frac{\frac{cos}{\sin^2}}{\frac{1}{cos}} \] \[ \huge \frac{\frac{cos}{\sin^2}}{\frac{1}{cos}} \times cos \] \[ \huge \frac{\frac{cos^2}{\sin^2}}{\frac{1}{cos}} \times cos \] \[ \huge \frac{\frac{cos^2}{\sin^2}}{1} \] \[ \huge \frac{cos^2}{sin^2} \] \[ \huge \cot^2 \]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0These things are fun :D
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