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Ibbutibbu.
 one year ago
Can someone plx help me?
3x + 4 = 5x + 4
Ibbutibbu.
 one year ago
Can someone plx help me? 3x + 4 = 5x + 4

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DecentNabeel
 one year ago
Best ResponseYou've already chosen the best response.0\[\left3x+4\right=5x+4\quad :\quad x=1\]

freckles
 one year ago
Best ResponseYou've already chosen the best response.23x+4=(5x+4) anyways you have two equations to solve: 3x+4=(5x+4) or also 3x+4=5x+4 then check solutions

Ibbutibbu.
 one year ago
Best ResponseYou've already chosen the best response.0i think the 1st oneis wrong

DecentNabeel
 one year ago
Best ResponseYou've already chosen the best response.0@Ibbutibbu. i am right x=1

freckles
 one year ago
Best ResponseYou've already chosen the best response.2one solution you will see not work out because both sides will not be the same

freckles
 one year ago
Best ResponseYou've already chosen the best response.2@DecentNabeel he might want to know how to get the solution

freckles
 one year ago
Best ResponseYou've already chosen the best response.2\[3x+4=(5x+4) \\ 3x+4=5x4 \\ 3x+5x=44 \\ 8x=8 \\ x=1 \\ \text{ then also } 3x+4=5x+4 \\ 3x5x=44 \\ 2x=0 \\ x=0 \] we can check both of these to see if they are actually solutions

freckles
 one year ago
Best ResponseYou've already chosen the best response.2but plugging them into the original equation

freckles
 one year ago
Best ResponseYou've already chosen the best response.2\[3x+4=5x+4 \\ \text{ for example are both of these true: } \\ 3(1)+4=5(1)+4 \\ 3(0)+4=5(0)+4\]

Ibbutibbu.
 one year ago
Best ResponseYou've already chosen the best response.0i think they are both correct

DecentNabeel
 one year ago
Best ResponseYou've already chosen the best response.0\[3x+4\ge \:0\:\mathrm{for}\:x\ge \:\frac{4}{3},\:\quad \mathrm{\therefore\:for}\:x\ge \:\frac{4}{3}\quad \left3x+4\right=3x+4\] \[3x+4<0\:\mathrm{for}\:x<\frac{4}{3},\:\quad \mathrm{\therefore\:for}\:x<\frac{4}{3}\quad \left3x+4\right=\left(3x+4\right)\] \[\mathrm{Evaluate\:the\:expression\:\in\:the\:following\:ranges:}\] \[x<\frac{4}{3},\:x\ge \:\frac{4}{3}\] \[\left(\left(3x+4\right)\right)=5x+4\quad :\quad x=0\] \[\left(3x+4\right)=5x+4\quad :\quad x=1\] combine the range \[\left(x<\frac{4}{3}\:\:\:\mathrm{and}\:\:\:\:x=0\right)\:\:\:\mathrm{or}\:\:\:\left(x\ge \:\frac{4}{3}\:\:\:\mathrm{and}\:\:\:\:x=1\right)\] x=1

freckles
 one year ago
Best ResponseYou've already chosen the best response.2well looking at that second equation I wrote: 3(0)+4=5(0)+4 0+4=0+4 4=4 4=4 <this isn't a true equation so x=0 is definitely not a solution

DecentNabeel
 one year ago
Best ResponseYou've already chosen the best response.0are you understand @freckles

freckles
 one year ago
Best ResponseYou've already chosen the best response.2what does that means "are you understand @freckles "

freckles
 one year ago
Best ResponseYou've already chosen the best response.2well if you don't understand my explanation here is another way to look at it @DecentNabeel \[3x+4=5x+4 \\ 3x+4=(5x+4) \\ \text{ we need } 5x+4 \le 0 \\ x \le \frac{4}{5}\] and x wasn't less than or equal to 4/5 but 1 is so x=1 is the only solution

Ibbutibbu.
 one year ago
Best ResponseYou've already chosen the best response.0well, this is getting interesting

freckles
 one year ago
Best ResponseYou've already chosen the best response.2oops 0 wasn't less than or equal to 4/5*

freckles
 one year ago
Best ResponseYou've already chosen the best response.2but I think what you meant to ask me earlier @DecentNabeel was "do you understand @freckles "

Ibbutibbu.
 one year ago
Best ResponseYou've already chosen the best response.0i have one question 7x  5 are the two things 7x + 5 and 7x  5 ???

freckles
 one year ago
Best ResponseYou've already chosen the best response.27x5 can be 7x5 or 7x+5 7x5 is 7x5 only when 7x5>=0 7x5 is (7x5) only when 7x5<=0

DecentNabeel
 one year ago
Best ResponseYou've already chosen the best response.0i said x=1 is the solution.. but you said that are not correct.. then finally you are agree with me :)

Ibbutibbu.
 one year ago
Best ResponseYou've already chosen the best response.0u guys have been awesome

freckles
 one year ago
Best ResponseYou've already chosen the best response.2I never disagreed with you @DecentNabeel

freckles
 one year ago
Best ResponseYou've already chosen the best response.2@DecentNabeel where above did I ever say x=1 wasn't the solution

freckles
 one year ago
Best ResponseYou've already chosen the best response.2@DecentNabeel I think you should reread the conversation above because you might have gotten lost somewhere along the way.

DecentNabeel
 one year ago
Best ResponseYou've already chosen the best response.0yes i cannot read the conversation above.. continue @freckles
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