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chris215

  • one year ago

Ball A moving along a straight line at 2 m/s collides elastically with ball B of same mass moving at -3 m/s. What is the velocity of the balls A and B after collision?

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  1. anonymous
    • one year ago
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    mass= force times acceleration

  2. anonymous
    • one year ago
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    you need conservation of momentum and conservation of kinetic energy equations. Let \(v_{A1}\) be initial velocity for ball A, \(v_{A2}\) be final velocity for ball 2, \(v_{B1}\) be initial velocity for ball B, and \(v_{B2}\) be final velocity for Ball B Momentum Conservation (P = mv, momentum = mass * velocity) \[P_1=P_2\] \[mv_{A1}+mv_{B1}=mv_{A2}+mv_{B2}\] All the masses are the same so they cancel \[v_{A1}+v_{B1}=v_{A2}+v_{B2}\] Plug in numbers for \(v_{A1}\) and \(v_{B1}\) \[2-3=v_{A2}+v_{B2}\] \[-1=v_{A2}+v_{B2}\] KE = ½mv² Do more or less the same thing to create a conservation of kinetic energy equation

  3. anonymous
    • one year ago
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    dame idk

  4. anonymous
    • one year ago
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    how about this way since it's multiple choice |dw:1435874747318:dw|

  5. anonymous
    • one year ago
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    oops |dw:1435875089386:dw|

  6. anonymous
    • one year ago
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    you're welcome

  7. chris215
    • one year ago
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    wait but none of the answers represent that

  8. anonymous
    • one year ago
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    are you sure?

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