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anonymous
 one year ago
Algebra Question
anonymous
 one year ago
Algebra Question

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0If \[\frac{ a }{ 2 } + \frac{ b }{ 2 } = 3 \] what is the value of 2a +2b?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I haven't really been able to get anywhere on it, any form of help will help :D

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0@slade well I don't really have any idea on how to start

freckles
 one year ago
Best ResponseYou've already chosen the best response.4I dare you to multiply both sides by 4

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0thats how u do it right there

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0what would that do? um okaay 3 x 4 = 12 on the right but i don't know how to multiply the fractions :/

freckles
 one year ago
Best ResponseYou've already chosen the best response.4do you know what 4/2=?

freckles
 one year ago
Best ResponseYou've already chosen the best response.4\[4(\frac{a}{2}+\frac{b}{2}) \\ =\frac{4}{2}a+\frac{4}{2}b=? \]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.02a + 2b is what i get! and that means it eqauls 3 !!

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0but what would make me multiply each side by 4?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I like your approach @freckles

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I dare you all to learn math :D double dog dare at that :D

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0to solve yes but where did you think of 4 why not 3? like is there a specific reason or thats just how algebra works? common factor what was it?

freckles
 one year ago
Best ResponseYou've already chosen the best response.4well 4(a/2+b/2) would give me what I want which is 2a+2b

freckles
 one year ago
Best ResponseYou've already chosen the best response.4but if I multiply one side by 4 I have to multiply the other side by 4

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0ah yes that is true that is how to get the end result

freckles
 one year ago
Best ResponseYou've already chosen the best response.4do you want to give you a problem that is similar ?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0@kevinhunterwood69 it is hard work but if you keep at it, it will get easier :D

freckles
 one year ago
Best ResponseYou've already chosen the best response.4solve for 6a+9b given \[2a+3b=1\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0no one is listening to me

freckles
 one year ago
Best ResponseYou've already chosen the best response.4@kevinhunterwood69 do you notice how to find the value of 6a+9b yet?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0okay so I did: solve for 6a + 9b given: 2a + 3b = 1 work: 2a + 3b = 1 3 (2a + 3b) = 1(3) 6a + 9b = 3 answer: 3

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0math is fun when i can finally understand algebra

freckles
 one year ago
Best ResponseYou've already chosen the best response.4good job I bet if that was the problem you had you would have had no problems do you think the fractions throw you off ?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0yes def fractions have always been a struggle to understand

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0square roots too but mostly fractions

freckles
 one year ago
Best ResponseYou've already chosen the best response.4try this one: \[\text{ If } a+\frac{b}{3}=4 \text{ then what is the value of } 21a+7b\] (this will has a fraction in it; let's see if it throws you off any this time )

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0if i move 3 to the other side will it be on top?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0actually wait i can't do that right ugh um if i move b let me see

freckles
 one year ago
Best ResponseYou've already chosen the best response.4so you want to multiply both sides 3 to remove the fraction you can do that 3a+b=12 but we still are not done

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0all i know is im trying to get constants on one side and variables on the other right?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0how did you get 3a and b lost its 3? oh you moved the 3 from b next to a?

freckles
 one year ago
Best ResponseYou've already chosen the best response.4\[a+\frac{b}{3}=4 \\ \text{ if you don't like the fraction there you can always multiply both sides by } \\ \text{ what is \in the denominator of that fraction } \\ 3(a+\frac{b}{3})=3(4) \\ 3(a)+3(\frac{b}{3})=3(4) \\ 3a+b=12\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0yes that explains it! thanks so much

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0well 3a i understand actually haha 3(b/3) = b?

freckles
 one year ago
Best ResponseYou've already chosen the best response.4\[3(\frac{b}{3})=3 \cdot \frac{b}{3}=\frac{3}{1} \cdot \frac{b}{3}= \frac{3}{3} \cdot \frac{b}{1}=1 \cdot b =b \]

freckles
 one year ago
Best ResponseYou've already chosen the best response.4basically in summary 3/3=1 so you are left with 1*b which is just b

freckles
 one year ago
Best ResponseYou've already chosen the best response.4like in your problem we had above we had: \[\frac{a}{2}+\frac{b}{2}=3 \\ \text{ we could have cleared the fractions before finding what we wanted } \\ \text{ by multiplying both sides by 2} \\ 2(\frac{a}{2}+\frac{b}{2})=2(3) \\ 2 \frac{a}{2}+2 \frac{b}{2}=2(3) \\ a+b=6\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0yes i follow up to the point 3/3 = b/1 why does b not become 3b? like 3/3 = 3b/1 ?

freckles
 one year ago
Best ResponseYou've already chosen the best response.4anything over itself is 1 (well except 0)

freckles
 one year ago
Best ResponseYou've already chosen the best response.4first do you know that 3/3=1 ?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0no time for jokes lol

freckles
 one year ago
Best ResponseYou've already chosen the best response.4\[\frac{3}{3}=1 \\ \text{ so if I multiply both sides by } b \text{ we have } \\ \frac{3}{3}b=1 b\]

freckles
 one year ago
Best ResponseYou've already chosen the best response.4is this not answering your question?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0so we were at 3a + b = 12

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0and m trying to figure out what is 21a + 7b so

freckles
 one year ago
Best ResponseYou've already chosen the best response.4right and we want 21a+7b 's value

freckles
 one year ago
Best ResponseYou've already chosen the best response.4any if you multiply both sides by s_v__ you will get?

freckles
 one year ago
Best ResponseYou've already chosen the best response.4I didn't put the full word there

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0then we multiply 12 by 7 that means :O

freckles
 one year ago
Best ResponseYou've already chosen the best response.4just so you know we could have figured out 21a+7b in one step

freckles
 one year ago
Best ResponseYou've already chosen the best response.4\[a+\frac{b}{3}=4 \\ \text{ we wanted } 21a+7b \\ \text{ so we could have just multiplied 21 on both sides \to \begin with } \\ 21a+21(\frac{b}{3})=21(4) \\ 21a+7b=84\]

freckles
 one year ago
Best ResponseYou've already chosen the best response.4anyways keep practicing and numbers will become easier to play with

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0thanks for all the extra practice!

freckles
 one year ago
Best ResponseYou've already chosen the best response.4np :) these can get a lot funnier I promise \[\text{ assume } a \text{ and } b \text{ are positive } \\\text{ if } a^2+2ab+b^2=4 \text{ then what is } (a+b)^4 \text{ or what is } a+b \] I think they can even get funnier than that

freckles
 one year ago
Best ResponseYou've already chosen the best response.4\[a^2+2ab+b^2=(a+b)^2 \text{ is the trick there }\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0welp i'll go back to this sat book

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0and ponder on about the funny stuff in math lol

mathstudent55
 one year ago
Best ResponseYou've already chosen the best response.0@freckles Great explanations!
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