## anonymous one year ago Solve the inequality. Show your work. 6y – 8 ≤ 10 This is what i got. Am i right or am i wrong? 6y -8 ≤ 10 -6y -6 -8 4 +8 12 y = 12 plug in 12 in place of the y 6+12 -7 ≤ 10 6+ 12 -7 is less then equal to 10

1. anonymous

Hmm.. your concept is correct, but here is the correct way to do it:

2. anonymous

How?

3. anonymous

|dw:1435874492127:dw| So in this step, you did -6y on both sides.. remember that you first need to subtract the single integer before doing anything to the coefficients.

4. anonymous

|dw:1435874558210:dw| It should have been set up like this then

5. anonymous

Do you follow?

6. anonymous

So i need to get rid of my negative number first?

7. anonymous

Even when you did "-6y" on both sides, you should have included your "y" with the 6.. you can't just get rid of y.

8. anonymous

No, you need to get rid of any number that doesn't have a variable with it.. regardless if it is negative or not.

9. anonymous

Oh alright

10. anonymous

Now we need to isolate the y variable. Do you have an idea as to how to do that?

11. anonymous

Hint: Apply inverse operations to the left side of inequality.

12. anonymous

If it's not subtracting it, then no.

13. anonymous

Okay.

14. anonymous

|dw:1435874740349:dw| You need to divide my 6 on both sides so the y is by itself. Since it is 6 times y, dividing 6y by 6 would make it just y.

15. anonymous

If you do something to one side of the inequality, you must do it on the other, too.

16. anonymous

How did you get 18?

17. anonymous

10 + 8 = 18

18. anonymous

The 8 is negative

19. anonymous

|dw:1435874840177:dw|

20. anonymous

Yes.. but I need to apply INVERSE operations to GET RID of it.

21. anonymous

Okay.

22. anonymous

there is no point in doing "-8" again.. makes no sense

23. anonymous

|dw:1435874888526:dw|

24. anonymous

18/6 = 3 So, y is less than or equal to 3.

25. anonymous

True didn't realize you added the 8 as part of the fraction.

26. anonymous

Alright. Thanks

27. anonymous

Hope I helped :)

28. anonymous

You did! Thanks.