- anonymous

Solve the inequality. Show your work.
6y – 8 ≤ 10
This is what i got. Am i right or am i wrong?
6y -8 ≤ 10
-6y -6
-8 4
+8 12
y = 12
plug in 12 in place of the y
6+12 -7 ≤ 10
6+ 12 -7 is less then equal to 10

- jamiebookeater

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- anonymous

Hmm.. your concept is correct, but here is the correct way to do it:

- anonymous

How?

- anonymous

|dw:1435874492127:dw|
So in this step, you did -6y on both sides.. remember that you first need to subtract the single integer before doing anything to the coefficients.

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## More answers

- anonymous

|dw:1435874558210:dw|
It should have been set up like this then

- anonymous

Do you follow?

- anonymous

So i need to get rid of my negative number first?

- anonymous

Even when you did "-6y" on both sides, you should have included your "y" with the 6.. you can't just get rid of y.

- anonymous

No, you need to get rid of any number that doesn't have a variable with it.. regardless if it is negative or not.

- anonymous

Oh alright

- anonymous

Now we need to isolate the y variable. Do you have an idea as to how to do that?

- anonymous

Hint: Apply inverse operations to the left side of inequality.

- anonymous

If it's not subtracting it, then no.

- anonymous

Okay.

- anonymous

|dw:1435874740349:dw|
You need to divide my 6 on both sides so the y is by itself. Since it is 6 times y, dividing 6y by 6 would make it just y.

- anonymous

If you do something to one side of the inequality, you must do it on the other, too.

- anonymous

How did you get 18?

- anonymous

10 + 8 = 18

- anonymous

The 8 is negative

- anonymous

|dw:1435874840177:dw|

- anonymous

Yes.. but I need to apply INVERSE operations to GET RID of it.

- anonymous

Okay.

- anonymous

there is no point in doing "-8" again.. makes no sense

- anonymous

|dw:1435874888526:dw|

- anonymous

18/6 = 3
So, y is less than or equal to 3.

- anonymous

True didn't realize you added the 8 as part of the fraction.

- anonymous

Alright. Thanks

- anonymous

Hope I helped :)

- anonymous

You did! Thanks.

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