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Is that \[f(x) = x^2 + x + 2; g(x) = 2x^2 + 5\]

yess

So you have to put g(x) in for f(x)

how

So that will be \[(2x^2 + 5)^2 + (2x^2 + 5) + 2 \]

Because you will be inputting every g(x) value into every x in the f(x) field.

so now do I combine like terms or?

So \[(4x^4 + 25) + (2x^2 + 5) + 2\]

Yes, you can combine like terms now

why did the 2 stay?

The 2 stayed because we were plugging in g(x) terms in for f(x)

So your final answer should look like \[4x^4 + 2x^2 +32\]

Because the "2" didn't have a variable next to it, we didn't have to mess with it.

ohh I see... thank you so much

Does that Help?

yes..but im very bad at it though

I feel you..wish I could help you too. I am taking algebra online but try this website.. mathway.com

@chrisdbest
\[(2x^2+5)^2 \neq 4x^4+25\]
you have to foil that
\[(2x^2+5)^2 = (2x^2+5)(2x^2+5)\]

Lols

So \[4x^4 + 10x^2 + 25 ?\] That's what you meant?

so confused

Did you get the right answer @ sharlin?

+20x² in the middle

Lols thats what I meant to pput. I'm dyslecix

* put; * dyslexic

im not sure because its not multiple choice

what would the final answer be?

\[4x^4 +20x^2 +25\]

Im stil confused on how you got there

Peachpi got this. I feel like he can explain it to you better than I can.

with me so far?

yes

so I got 4x^2+10x^2+10x^2+25

I get a crazy answer

thx @chrisdbest

4x4+22x2+32..idk

that's right

really..im really not sure

yep. trust your work