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anonymous

  • one year ago

PLEAASEE HELP...will medal and fan...Let f(x) = x2 + x + 2 and g(x) = 2x2 + 5. Find f(g(x)).

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  1. chrisdbest
    • one year ago
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    Is that \[f(x) = x^2 + x + 2; g(x) = 2x^2 + 5\]

  2. anonymous
    • one year ago
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    yess

  3. chrisdbest
    • one year ago
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    So you have to put g(x) in for f(x)

  4. anonymous
    • one year ago
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    how

  5. chrisdbest
    • one year ago
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    So that will be \[(2x^2 + 5)^2 + (2x^2 + 5) + 2 \]

  6. chrisdbest
    • one year ago
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    Because you will be inputting every g(x) value into every x in the f(x) field.

  7. anonymous
    • one year ago
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    so now do I combine like terms or?

  8. chrisdbest
    • one year ago
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    So \[(4x^4 + 25) + (2x^2 + 5) + 2\]

  9. chrisdbest
    • one year ago
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    Yes, you can combine like terms now

  10. anonymous
    • one year ago
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    why did the 2 stay?

  11. chrisdbest
    • one year ago
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    The 2 stayed because we were plugging in g(x) terms in for f(x)

  12. chrisdbest
    • one year ago
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    So your final answer should look like \[4x^4 + 2x^2 +32\]

  13. chrisdbest
    • one year ago
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    Because the "2" didn't have a variable next to it, we didn't have to mess with it.

  14. anonymous
    • one year ago
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    ohh I see... thank you so much

  15. chrisdbest
    • one year ago
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    Does that Help?

  16. anonymous
    • one year ago
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    yes..but im very bad at it though

  17. chrisdbest
    • one year ago
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    I feel yah man, I need help in Pre-Calc because there are some parts in Pre-Calc that I go str8 to OS for. Even though I'm taking Pre-Calc online, I'm getting 90% of my answers from OS.

  18. anonymous
    • one year ago
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    I feel you..wish I could help you too. I am taking algebra online but try this website.. mathway.com

  19. anonymous
    • one year ago
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    @chrisdbest \[(2x^2+5)^2 \neq 4x^4+25\] you have to foil that \[(2x^2+5)^2 = (2x^2+5)(2x^2+5)\]

  20. chrisdbest
    • one year ago
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    Lols

  21. chrisdbest
    • one year ago
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    So \[4x^4 + 10x^2 + 25 ?\] That's what you meant?

  22. anonymous
    • one year ago
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    so confused

  23. chrisdbest
    • one year ago
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    Did you get the right answer @ sharlin?

  24. anonymous
    • one year ago
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    +20x² in the middle

  25. chrisdbest
    • one year ago
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    @sharlin ?

  26. chrisdbest
    • one year ago
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    Lols thats what I meant to pput. I'm dyslecix

  27. chrisdbest
    • one year ago
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    * put; * dyslexic

  28. anonymous
    • one year ago
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    im not sure because its not multiple choice

  29. freckles
    • one year ago
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    @peachpi was just talking about how (a+b)^2=a^2+2ab+b^2 instead of a^2+b^2 so changes will need to be made to your previous answer @sharlin

  30. anonymous
    • one year ago
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    what would the final answer be?

  31. chrisdbest
    • one year ago
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    \[4x^4 +20x^2 +25\]

  32. anonymous
    • one year ago
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    Im stil confused on how you got there

  33. anonymous
    • one year ago
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    He made the substitution and got \[f(g(x))=(2x^2+5)^2+(2x^2+5)+2\] which is the same as \[f(g(x))=(2x^2+5)(2x^2+5)+(2x^2+5)+2\] He multiplied and then combined like terms

  34. chrisdbest
    • one year ago
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    Peachpi got this. I feel like he can explain it to you better than I can.

  35. anonymous
    • one year ago
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    with me so far?

  36. anonymous
    • one year ago
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    yes

  37. anonymous
    • one year ago
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    ok. now multiply (2x² +5)(2x² + 5) either using foil or the rule @freckles put up

  38. anonymous
    • one year ago
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    so I got 4x^2+10x^2+10x^2+25

  39. anonymous
    • one year ago
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    Should be 4x^4. so that was just the first part of the equation. You need to combine it with the rest and combine like terms 4x^4+10x^2+10x^2+25 + 2x^2+ 5 +2

  40. anonymous
    • one year ago
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    I get a crazy answer

  41. chrisdbest
    • one year ago
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    Yo @peachpi Ima give you dat gold medal cuz I think you deserve it, cuz I don't got a lot of time to answer everyone's questions.

  42. anonymous
    • one year ago
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    @sharlin what did you get?

  43. anonymous
    • one year ago
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    thx @chrisdbest

  44. anonymous
    • one year ago
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    4x4+22x2+32..idk

  45. anonymous
    • one year ago
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    that's right

  46. anonymous
    • one year ago
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    really..im really not sure

  47. anonymous
    • one year ago
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    yep. trust your work

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