anonymous
  • anonymous
plz help medal + fan + testimonial show all the work ( explain) do not use a calculator for parts 1-4. Let f be the function defined as follows:
Calculus1
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
schrodinger
  • schrodinger
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
|dw:1435882692544:dw|
anonymous
  • anonymous
1. if a=2 and b=3, is f continuous at x=1? justify your answer. 2. find a relationship between a and b for which f is continuous at x=1. ( Hint: A relationship between a and b just means an equation in a and b. 3. Find a relationship between a and b so that f is continuous at x=2. 4. USe your equations from parts (ii)and(III) to find the values of a and b so that f is continuous at both x=1 and at x=2? 5. Graph the piece function using the values of a and b that you have found. you may graph by hand or use your calculator to graph.
Loser66
  • Loser66
Any idea?

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

anonymous
  • anonymous
no im completely clueless in this! o.o
Loser66
  • Loser66
1) No, since we don't have x =1 on f(x). (The way they define f(x) excludes 1) 2) if f(x) is continuous at x =1, that is the first part = second part (in f(x) I meant if x =1, then y =2 (for f(x) =3-x) Plug it into the second one ax^2 + bx =y with x =1, y =2 to have the relationship between a and b 3) do the same with the second part and the third part for x =2 That is if x =2, y = 0 (for y = 5x-10) Now we have (2,0) , replace in ax^2+bx =y to get the relationship between them.
Loser66
  • Loser66
4) combine part 2 and part 3 to solve for a, b. We have 2 equations, 2 unknowns --> the system is solvable. 5) graph, this part is the easiest part. I think you can do it, right?
anonymous
  • anonymous
huuuuuuhhhhh? o.ohow did you get that?
Loser66
  • Loser66
You asked "how did I get that?" , right? of course, I got it from the courses I took in the past.
anonymous
  • anonymous
lol I mean how did you arrive to the answers?
Loser66
  • Loser66
I don't get what you mean. My logic is all in what I said. Read and you can see how, why and answer.
anonymous
  • anonymous
ok if I need any more help can I message you
anonymous
  • anonymous
you got this?
anonymous
  • anonymous
is there anything you wold like to add?
anonymous
  • anonymous
i was just wondering if you got the answer the question is just walking you through it step by step
anonymous
  • anonymous
not really im tryig on my own lol. but I am terrible. even with the steps which I appreciate , I am having a little trouble getting to the answer.
anonymous
  • anonymous
this is what you do plug in 1 for \(x\) in both \(3-x\) and \(ax^2+bx\) you get \[3-1=2\] and \[a+b\] setting them equal tells you \[a+b=2\]
anonymous
  • anonymous
then plug in \(2\) in \(ax^2+bx\) and \(5x-10\) you get \[4a+2b\] and \[2\times 2-1=0\] telling you \[4a+b=0\]
anonymous
  • anonymous
is this for number one?
anonymous
  • anonymous
now you have \[a+b=2\\ 4a+2b=0\] solve that for \(a\) and \(b\) and you are done
anonymous
  • anonymous
wait do I plug in a+b=2 into 4a+2b=0?
anonymous
  • anonymous
you solve the "system of equations" just as normal \[a+b=2\\ 4a+2b=0\] you can solve it using any method you like (or know)
anonymous
  • anonymous
ok this is what I get: 4a^2+ 2b^2=2

Looking for something else?

Not the answer you are looking for? Search for more explanations.