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anonymous
 one year ago
plz help medal + fan + testimonial
show all the work ( explain)
do not use a calculator for parts 14.
Let f be the function defined as follows:
anonymous
 one year ago
plz help medal + fan + testimonial show all the work ( explain) do not use a calculator for parts 14. Let f be the function defined as follows:

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0dw:1435882692544:dw

anonymous
 one year ago
Best ResponseYou've already chosen the best response.01. if a=2 and b=3, is f continuous at x=1? justify your answer. 2. find a relationship between a and b for which f is continuous at x=1. ( Hint: A relationship between a and b just means an equation in a and b. 3. Find a relationship between a and b so that f is continuous at x=2. 4. USe your equations from parts (ii)and(III) to find the values of a and b so that f is continuous at both x=1 and at x=2? 5. Graph the piece function using the values of a and b that you have found. you may graph by hand or use your calculator to graph.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0no im completely clueless in this! o.o

Loser66
 one year ago
Best ResponseYou've already chosen the best response.11) No, since we don't have x =1 on f(x). (The way they define f(x) excludes 1) 2) if f(x) is continuous at x =1, that is the first part = second part (in f(x) I meant if x =1, then y =2 (for f(x) =3x) Plug it into the second one ax^2 + bx =y with x =1, y =2 to have the relationship between a and b 3) do the same with the second part and the third part for x =2 That is if x =2, y = 0 (for y = 5x10) Now we have (2,0) , replace in ax^2+bx =y to get the relationship between them.

Loser66
 one year ago
Best ResponseYou've already chosen the best response.14) combine part 2 and part 3 to solve for a, b. We have 2 equations, 2 unknowns > the system is solvable. 5) graph, this part is the easiest part. I think you can do it, right?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0huuuuuuhhhhh? o.ohow did you get that?

Loser66
 one year ago
Best ResponseYou've already chosen the best response.1You asked "how did I get that?" , right? of course, I got it from the courses I took in the past.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0lol I mean how did you arrive to the answers?

Loser66
 one year ago
Best ResponseYou've already chosen the best response.1I don't get what you mean. My logic is all in what I said. Read and you can see how, why and answer.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0ok if I need any more help can I message you

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0is there anything you wold like to add?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0i was just wondering if you got the answer the question is just walking you through it step by step

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0not really im tryig on my own lol. but I am terrible. even with the steps which I appreciate , I am having a little trouble getting to the answer.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0this is what you do plug in 1 for \(x\) in both \(3x\) and \(ax^2+bx\) you get \[31=2\] and \[a+b\] setting them equal tells you \[a+b=2\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0then plug in \(2\) in \(ax^2+bx\) and \(5x10\) you get \[4a+2b\] and \[2\times 21=0\] telling you \[4a+b=0\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0is this for number one?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0now you have \[a+b=2\\ 4a+2b=0\] solve that for \(a\) and \(b\) and you are done

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0wait do I plug in a+b=2 into 4a+2b=0?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0you solve the "system of equations" just as normal \[a+b=2\\ 4a+2b=0\] you can solve it using any method you like (or know)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0ok this is what I get: 4a^2+ 2b^2=2
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