At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga.
Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus.
Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get our expert's

answer on brainly

SEE EXPERT ANSWER

Get your **free** account and access **expert** answers to this and **thousands** of other questions.

I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your **free** account and access **expert** answers to this and **thousands** of other questions

Getting the table, one moment

Time (hours) 0 1 2 3 4 5 6
Population (1000s) 5.1 3.03 1.72 1.17 1.38 2.35 4.08

how are you supposed to do this (just asking because you have to "show work")

I have no clue lol I typed everything the question asked and the table

@DecentNabeel i am not sure that would work, since it is not exact

im confused

@satellite73 many way for solve i solve another but this is true

if it is exact you can do it using only three points
\[(0,5.1),(1,3.03),(2,2.35)\] or any other 3

yes is correct

also you do not have to solve a system of three equations, only two

So lets write step one so i can start writing it so i can show our work lol

the part you wrote above is correct

5.1 = a*0^2 + b*0 + c
3.03 = a*1^2 + b*1 + c
2.35 = a*5^2 + b*5 + c
solve of a, b and c

I dont know how to plug all that in

oops second one is
\[3.03=a+b=5.1\] so \[a+b=-2.07\]

do you see how @DecentNabeel got this one
\[5.1 = a*0^2 + b*0 + c\]

if the answer is "no" that is fine, just say so

yes c=5.1 @satellite73

no i dont get it

ok do you get that you are trying to find \(a,b\) and \(c\) to make up
\[y=ax^2+bx+c\]?

yes

ok and from the table you see that \((0,5.1)\) is on the graph right?

correct

that means if \(x=0\) then \(y=5.1\) right ?

correct

What @LynFran ????

@satellite73 are you back? The serve kicked me off

yea me too

@EllenJaz17 what are you said @LynFran

they interrupted me learning lol

lol

lol

is that ok?

yes i get that one because its easy because x is 0 lol

right so that tells us right away that \(c=5.1\) yes?

correct

ok now \(a\) and \(b\) to go

ok im ready

the next point we have is \((1,3.03)\) right ?

yes

this also cleans up nicely, since \(1^2=1\) we have
\[3.03=a+b+5.1\]

good so far?

yes

how we doing so far?

good

|dw:1435898261868:dw|

ok now one more equation to go
you can pick any point you like but i will pick \((2,1.72)\)

Sounds good

good @satellite73

again we have
\[y=ax^2+bx+5.1\] put \(x=2,y=1.72\) and get
\[1.72=a\times 2^2+b\times 2+5.1\]

ok with that?

yes

now we clean it up
actually you can
what do you get in terms of \(a,b\) and a number ?

\[-2.07^{2}+1.72+5.1\] ? Im sure that's wrong

quite wrong, it is much easier than that

haha oh jeez. I needed this class apparently very much lol and your help

lets go back to \[1.72=a\times 2^2+b\times 2+5.1\]

your equation will have an \(a\) and a \(b\) in it
all you have to do is compute \(2^2\)

So a=4?

no just \(a\times 4\) or \(4a\)

lets back up a second

if you are still confused, say so and i will spell it out

Yeah im confused

thought so
i am just going to rewrite \[1.72=a\times 2^2+b\times 2+5.1\]

since \(2^2-4\) this is the same as
\[1.72=a\times 4+b\times 2+5.1\] clear?

yes

i meant "since \(2^2=4\)

ok now we just make it look better
\[1.72=4a+2b+5.1\] go that ?

yes

again we subtract \(5.1\) from both sides and arrive finally at
\[4a+2b=-3.38\]

ok

now lets get those two equations together
\[a+b=-2.07\\
4a+2b=-3.38\]

damn \[a+b=-2.07\\
4a+2b=-3.38\] thats better

we have to solve this "system of equations" to find \(a\) and \(b\)

sounds good

do you know how to solve this system?

no

i hate decimals, at this point i would cheat, but you can do whatever you like

do you have to show ALL your steps?

no it just says show work

well we have come this far, lets grind it out

ok im just writing as you go

so all thats left to find is b, than we do the equation, correct?

now we know that \(a=.33\) and
\[a+b=-2.07\] you have
\[.33+b=-2.07\] so \[b=-2.4\]

yeah that is it , find \(a\) and \(b\)
we get \(a=.33\) and \(b=-2.4\)

and we recall that \(c=5.1\)

dang i made a mistake somewheres \(b=-2.45\) actually but whatever

So .33^2-2.45+5.1

oh damn damn damn i made a stupid typo

everywhere you see \(.33\) replace it by \(.38\)

i told you i hate decimals
when you solve \[4a+2(-2.07-a)=-3.38\] you get \(a=.38\)

and since \(a=.38\) we get \(b=-2.45\)
final answer
\[y=.33x^2-2.45x+5.1\]

your math teacher must hate you to give you such a mess

should it say y=.38 or y=.33 lol

Final Answer
\[\huge \color{red}{y=.38x^2-2.45x+5.1}\]

lol great thank you so much!

|dw:1435900099694:dw|

Do you wanna help me with another question that relates to this table lmao @satellite73

hell no
not without a shot of tequila

ok post i will take a look, maybe it will be easier

ooh to

THIS TABLE ok

|dw:1435900241301:dw|

There you go lmao

good, no lime or salt (for sissies)

bahaha

what is the question i am about to turn in to a pumpkin

@satellite73 sorry are you still there