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anonymous
 one year ago
please help!
Domain and range of:
a. f(x)= 1/x+3
b. g(x)= sqrt(x+6)
anonymous
 one year ago
please help! Domain and range of: a. f(x)= 1/x+3 b. g(x)= sqrt(x+6)

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rishavraj
 one year ago
Best ResponseYou've already chosen the best response.3is it \[\frac{ 1 }{ x + 3 }~~~~~or ~~~~~~\frac{ 1 }{ x } + 3\]

rishavraj
 one year ago
Best ResponseYou've already chosen the best response.3if its \[\frac{ 1 }{ x + 3 }\] then the denominator can't be zero. i.e.\[x + 3 \neq 0\] so \[x \neq 3\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0ok thanks! what about range? and the other ones

rishavraj
 one year ago
Best ResponseYou've already chosen the best response.3did u get the domain ????

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0i got the first one! @rishavraj

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0and i think i got sqrt(x+3) but i'm not sure

rishavraj
 one year ago
Best ResponseYou've already chosen the best response.3the functn in sqrt can't be negative.... so \[x + 3 \ge 0\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0oops the question was actually sqrt (x+6) so x≥6 ?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0or is it x>6? because couldn't it be sqrt(66)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0oh oops i meant 6, but still why isn't it x>6

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0you looking for the range of \[f(x)=\frac{1}{x+3}\]?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0i got all real numbers but not sure

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0a fraction is only zero if the numerator is zero

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0therefore \[\frac{1}{x+3}\] cannot be zero because the numerator is 1

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0range is all real numbers except zero

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0oh! oops. thanks! what about sqrt(x+6) and h(x)=x^3+2x+5

rishavraj
 one year ago
Best ResponseYou've already chosen the best response.3its clear the its domain and range is ALL REAL Numbers... i.e R

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0which one are we talking about :/

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0\[\sqrt{x+6}\] the square root of anything is never less that zero range \[y\geq 0\]

rishavraj
 one year ago
Best ResponseYou've already chosen the best response.3about h(x) = x^3 + 2x + 5

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0cube goes from \(\infty\) to \(+\infty\)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0oh, ok thanks! and im still confused about the sqrt one?

rishavraj
 one year ago
Best ResponseYou've already chosen the best response.3bcoz it can be even zero thts why.....

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0oh. why is the domain x≥6

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0i thought it could be sqrt0 or no

rishavraj
 one year ago
Best ResponseYou've already chosen the best response.3see the function in sqrt can never be negative...... so \[x + 6 \geq 0\] \[x \geq 6\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0oh okay thank you so much!
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