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anonymous

  • one year ago

An arrow travelling at 45 m/s strikes and embeds itself in a 450 g apple which is initially at rest. They move off horizont ally at 12 m/s after impact. What is the mass of the arrow?

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  1. anonymous
    • one year ago
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    i did m(45)+(0)(450)=(450)(12), what am i doing wrong ? @Michele_Laino

  2. Michele_Laino
    • one year ago
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    the right equation, is: \[\Large m \times 45 + 0 \times 450 = \left( {m + 450} \right) \times 12\]

  3. anonymous
    • one year ago
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    i havve to find 1 m so why is their two

  4. anonymous
    • one year ago
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    ?

  5. Michele_Laino
    • one year ago
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    since after the impact, te arrow and the apple are ambedded each other, so their momentum is: \[\Large \left( {m + 450} \right) \times 12\;\frac{{{\text{grams}} \times {\text{m}}}}{{{\text{sec}}}}\]

  6. Michele_Laino
    • one year ago
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    after a simple computation, we get: \[\Large m = \frac{{450 \times 12}}{{33}} = ...{\text{grams}}\]

  7. anonymous
    • one year ago
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    what happned to the other "m"?

  8. anonymous
    • one year ago
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    when we simplify it ?

  9. anonymous
    • one year ago
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    @Michele_Laino

  10. Michele_Laino
    • one year ago
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    the mass of apple is 450 grams

  11. anonymous
    • one year ago
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    i mean the m on the left side

  12. anonymous
    • one year ago
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    when we solve for one variable you can't have 2

  13. Michele_Laino
    • one year ago
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    here are more steps: \[\Large \begin{gathered} m \times 45 + 0 \times 450 = \left( {m + 450} \right) \times 12 \hfill \\ 45m = 12m + 450 \times 12 \hfill \\ 33m = 450 \times 12 \hfill \\ \end{gathered} \]

  14. anonymous
    • one year ago
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    ohhh

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