An arrow travelling at 45 m/s strikes and embeds itself in a 450 g apple which is initially at rest. They move off horizont ally at 12 m/s after impact. What is the mass of the arrow?

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An arrow travelling at 45 m/s strikes and embeds itself in a 450 g apple which is initially at rest. They move off horizont ally at 12 m/s after impact. What is the mass of the arrow?

Physics
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i did m(45)+(0)(450)=(450)(12), what am i doing wrong ? @Michele_Laino
the right equation, is: \[\Large m \times 45 + 0 \times 450 = \left( {m + 450} \right) \times 12\]
i havve to find 1 m so why is their two

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since after the impact, te arrow and the apple are ambedded each other, so their momentum is: \[\Large \left( {m + 450} \right) \times 12\;\frac{{{\text{grams}} \times {\text{m}}}}{{{\text{sec}}}}\]
after a simple computation, we get: \[\Large m = \frac{{450 \times 12}}{{33}} = ...{\text{grams}}\]
what happned to the other "m"?
when we simplify it ?
the mass of apple is 450 grams
i mean the m on the left side
when we solve for one variable you can't have 2
here are more steps: \[\Large \begin{gathered} m \times 45 + 0 \times 450 = \left( {m + 450} \right) \times 12 \hfill \\ 45m = 12m + 450 \times 12 \hfill \\ 33m = 450 \times 12 \hfill \\ \end{gathered} \]
ohhh

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