Get our expert's

answer on brainly

SEE EXPERT ANSWER

Get your **free** account and access **expert** answers to this and **thousands** of other questions.

I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your **free** account and access **expert** answers to this and **thousands** of other questions

i know how to do it when they give me x but they gave my y instead

|dw:1435907166360:dw| ok first lets just plug what we have, then we will see what formula to use.

yea

we can plug in h k and y

but not x and p

x = h - p

|dw:1435908052023:dw| right?

so the directrix would be 0?

ohhhh ok

Ok cool, so our graph looks something like this |dw:1435908205110:dw| now we can write the equation

|dw:1435908337698:dw|

so p would be 10?

Nope, not 10, but 9, sorry about the picture, I just put 10 there to give an idea of the scale.

oh ok yea i see the 9 now

Alright cool, now just plug in all the value and standard form is in the following: \[x=ay^2+by+c\]

but in the answer choice the closest thing to 9 for p is -9, would -9 be right?

Yup, -9 is good

oh wait isnt it 1/4p?

y^2= 1/4px

May I see your answer choices actually

y = -1/9x^2
y2 = -36x
y = -1/36x
y2 = -9x

wouldnt it be c

Ok I see so it wants it in \[y = \frac{ 1 }{ 4 p}(x-h)^2+k\] form

That looks good to me

ok thank you! could you help me with one more but ill make a new post so i can give u another medal

That should be x^2 though

y=-1/36x^2

yea its x^2 i forgot to put the ^2

Ok :)

\[y = -\frac{ 1 }{ 36 }x^2\] so just in case, that is your final answer

ok thank you