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dix123
 one year ago
how to find solutions of a quadratic trinomial with a discriminant of 40.
dix123
 one year ago
how to find solutions of a quadratic trinomial with a discriminant of 40.

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dix123
 one year ago
Best ResponseYou've already chosen the best response.0Plssssssss helppppppppppp

UnkleRhaukus
 one year ago
Best ResponseYou've already chosen the best response.5A general quadratic polynomial: \[ax^2+bx+c=0\] The discriminant \(\Delta\): \[\Delta= b^24ac\]

dix123
 one year ago
Best ResponseYou've already chosen the best response.0but how do you get the solutions if the discriminant is a positive number, but not a perfect square. I mean I know it has 2 irrational solutions how would you solve it?

UnkleRhaukus
 one year ago
Best ResponseYou've already chosen the best response.5the solutions are given from the quadratic formula \[x=\frac{b\pm\sqrt{b^24ac}}{2a}=\frac{b\pm\sqrt{\Delta}}{2a}\]

dix123
 one year ago
Best ResponseYou've already chosen the best response.0Thank you. That really helps

UnkleRhaukus
 one year ago
Best ResponseYou've already chosen the best response.5If you found the discriminant to be positive, +40: then then irrational roots will be \[x=\frac{b\pm\sqrt{40}}{2a}\\ \quad=\frac{b\pm2\sqrt{10}}{2a}\\\] \[x=\frac{b+2\sqrt{10}}{2a},\quad \frac{b2\sqrt{10}}{2a}\\ \quad =\qquad\qquad\quad,\]
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