## dix123 one year ago how to find solutions of a quadratic trinomial with a discriminant of 40.

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1. dix123

Plssssssss helppppppppppp

2. UnkleRhaukus

A general quadratic polynomial: $ax^2+bx+c=0$ The discriminant $$\Delta$$: $\Delta= b^2-4ac$

3. dix123

but how do you get the solutions if the discriminant is a positive number, but not a perfect square. I mean I know it has 2 irrational solutions how would you solve it?

4. UnkleRhaukus

the solutions are given from the quadratic formula $x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}=\frac{-b\pm\sqrt{\Delta}}{2a}$

5. dix123

Thank you. That really helps

6. UnkleRhaukus

If you found the discriminant to be positive, +40: then then irrational roots will be $x=\frac{-b\pm\sqrt{40}}{2a}\\ \quad=\frac{-b\pm2\sqrt{10}}{2a}\\$ $x=\frac{-b+2\sqrt{10}}{2a},\quad \frac{-b-2\sqrt{10}}{2a}\\ \quad =\qquad\qquad\quad,$

7. dix123

Thank you!!!!