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dix123

  • one year ago

how to find solutions of a quadratic trinomial with a discriminant of 40.

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  1. dix123
    • one year ago
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    Plssssssss helppppppppppp

  2. UnkleRhaukus
    • one year ago
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    A general quadratic polynomial: \[ax^2+bx+c=0\] The discriminant \(\Delta\): \[\Delta= b^2-4ac\]

  3. dix123
    • one year ago
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    but how do you get the solutions if the discriminant is a positive number, but not a perfect square. I mean I know it has 2 irrational solutions how would you solve it?

  4. UnkleRhaukus
    • one year ago
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    the solutions are given from the quadratic formula \[x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}=\frac{-b\pm\sqrt{\Delta}}{2a}\]

  5. dix123
    • one year ago
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    Thank you. That really helps

  6. UnkleRhaukus
    • one year ago
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    If you found the discriminant to be positive, +40: then then irrational roots will be \[x=\frac{-b\pm\sqrt{40}}{2a}\\ \quad=\frac{-b\pm2\sqrt{10}}{2a}\\\] \[x=\frac{-b+2\sqrt{10}}{2a},\quad \frac{-b-2\sqrt{10}}{2a}\\ \quad =\qquad\qquad\quad,\]

  7. dix123
    • one year ago
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    Thank you!!!!

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