Find the standard form of the equation of the parabola with a vertex at the origin and a focus at (0, -7). @astrophysics

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Find the standard form of the equation of the parabola with a vertex at the origin and a focus at (0, -7). @astrophysics

Mathematics
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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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this one is harder because it only gives u the focus
|dw:1435909082458:dw| not really, it's sort of similar to your other one
Can you figure out the directrix, remember how I said vertex is in the middle of directrix and focus, so your directrix will be?

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so it would be 7?
@Astrophysics or (0,7)?
Yes, good! |dw:1435909595769:dw| see how it's similar now to your previous question?
So what way will the parabola go?
you said it cant pass the directrix right?
Yup!
so it will go down?
sorry im bad with determining which way the parabola goes
|dw:1435910277561:dw| same as previous actually, remember it cannot pass the directrix
\[y = \frac{ 1 }{ 4p }(x-h)^2+k\] similar as previous question except now we have -7 as our p
so i was right when i said down, haha im getting better atleast
Yes you are :)
y = -1/7x^2 y2 = -7x y =-1/28x^2 y2 = -28x
y=-1/28x^2?
Yeah, that sounds good
thank you!
Np, also notice the negative represents the vertical reflection, meaning the parabola will open down :), just a hint on the way to draw it if you get stuck :P

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