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anonymous

  • one year ago

Find the standard form of the equation of the parabola with a vertex at the origin and a focus at (0, -7). @astrophysics

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  1. anonymous
    • one year ago
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    this one is harder because it only gives u the focus

  2. Astrophysics
    • one year ago
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    |dw:1435909082458:dw| not really, it's sort of similar to your other one

  3. Astrophysics
    • one year ago
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    Can you figure out the directrix, remember how I said vertex is in the middle of directrix and focus, so your directrix will be?

  4. anonymous
    • one year ago
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    so it would be 7?

  5. anonymous
    • one year ago
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    @Astrophysics or (0,7)?

  6. Astrophysics
    • one year ago
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    Yes, good! |dw:1435909595769:dw| see how it's similar now to your previous question?

  7. Astrophysics
    • one year ago
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    So what way will the parabola go?

  8. anonymous
    • one year ago
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    you said it cant pass the directrix right?

  9. Astrophysics
    • one year ago
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    Yup!

  10. anonymous
    • one year ago
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    so it will go down?

  11. anonymous
    • one year ago
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    sorry im bad with determining which way the parabola goes

  12. Astrophysics
    • one year ago
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    |dw:1435910277561:dw| same as previous actually, remember it cannot pass the directrix

  13. Astrophysics
    • one year ago
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    \[y = \frac{ 1 }{ 4p }(x-h)^2+k\] similar as previous question except now we have -7 as our p

  14. anonymous
    • one year ago
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    so i was right when i said down, haha im getting better atleast

  15. Astrophysics
    • one year ago
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    Yes you are :)

  16. anonymous
    • one year ago
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    y = -1/7x^2 y2 = -7x y =-1/28x^2 y2 = -28x

  17. anonymous
    • one year ago
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    y=-1/28x^2?

  18. Astrophysics
    • one year ago
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    Yeah, that sounds good

  19. anonymous
    • one year ago
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    thank you!

  20. Astrophysics
    • one year ago
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    Np, also notice the negative represents the vertical reflection, meaning the parabola will open down :), just a hint on the way to draw it if you get stuck :P

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