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  • one year ago

Anyone?? please help! will give metal! Is my math on this correct? How many grams of magnesium oxide can be produced when 97.2 g Mg react with 88.5 g O2? Unbalanced equation: Mg + O2 → MgO Show, or explain, all of your work along with the final answer. Balanced equation: 2Mg + O2 --> 2MgO Mass of Mg = 97.2g Mg Molar mass of Mg = 24.3050g Mg Mass of O2 = 88.5g O2 Molar mass of O2 = 32g O2 Mass of MgO = ? Molar mass of MgO = 40.304g MgO ?g MgO = 97.2g Mg x (1mol Mg / 24.3050g Mg) x (2mol MgO / 2mol Mg) x (40.304g MgO / 1mol MgO) =97.2 x 2 x 40.304 / 24.3050 / 2 = 161.2g MgO Answer for first calculation = 161.2g MgO ?g MgO = 88.5g

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  1. anonymous
    • one year ago
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    @thomaster ? is this correct so far?

  2. Photon336
    • one year ago
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    What compound was your limiting reagent and why? You always use the limiting reagent to calculate how any grams of products.

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