anonymous
  • anonymous
If (x+7)(x-2) = ax^2 + bx + c for all values of x, where a, b, and c are constants, what is the value of a + b - c
Mathematics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
chestercat
  • chestercat
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
amoodarya
  • amoodarya
expand (x+7)(x-2) then compare rhs ,lhs
UsukiDoll
  • UsukiDoll
that's what I was thinking too... if we use the FOIL method to expand (x+7)(x-2) we can figure out what a, b, and c is
amoodarya
  • amoodarya
\[(x+7)(x-2)=x^2+5x-14=ax^2+bx+c\\ax^2=x^2\\bx=5x\\c=-14\]

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

amoodarya
  • amoodarya
another method is : put for example x=0,1,2 both side then you have a system of equation to find a,b,c
anonymous
  • anonymous
ohhh okay! It makes much more sense now! Thanks guys!! :)
UsukiDoll
  • UsukiDoll
it looked like a simple proof problem where we start from the left side and have it equal to the right side, so by expanding (x+7)(x-2) using FOIL we will have \[x^2+5x-14 \]. Then we compare that equation to \[ax^2+bx+c \] which is the standard quadratic equation.
anonymous
  • anonymous
Got it! Thank you!

Looking for something else?

Not the answer you are looking for? Search for more explanations.