anonymous
  • anonymous
Is this right or wrong? 11. Solve the inequality. Show your work. |r + 3| ≥ 7 | r + 3|≥ 7 -3 -3 | r | ≥ 4 If I plug the the 4 into r's place |4+3| ≥7
Mathematics
chestercat
  • chestercat
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Loser66
  • Loser66
for absolute value problem, you need do: \(| r+3|\geq 7\) \(-7\geq r+3\geq 7\) \(\bullet \) first and middle : \(-7 \geq r+3 \) -3 both sides \(-11\geq r\), that means \(r\leq -11\) (namely *) \(\bullet\) middle and last: \(r+3\geq 7\) -3 both sides, \(r\geq 4\) (namely **) Combine * and **, you have either \(r\leq -11\) or \(r\geq 4\) is the solution for the expression.
Loser66
  • Loser66
|dw:1435930768684:dw|
Loser66
  • Loser66
|dw:1435930801109:dw|

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Loser66
  • Loser66
|dw:1435930869866:dw|
Loser66
  • Loser66
Hence, your answer should be both with OR between them. I meant \(r\leq -11\) OR \(r\geq 4\)
anonymous
  • anonymous
So i have to move my 7 over to the left?
anonymous
  • anonymous
Okay.
Loser66
  • Loser66
Actually, you NOT move 7, just put -7 to the left.
anonymous
  • anonymous
Do the original 7 stay on or do i subtract it?
Loser66
  • Loser66
stay!! just put an extra value by opposite of 7 to the left.
Loser66
  • Loser66
In general, if |a| < 7, to solve it, you put one more value on the left by opposite value of number , like -7
anonymous
  • anonymous
Okay. Do i include it when i'm subtarcting 3?
Loser66
  • Loser66
if |a|> 7, again, put one more value on the left -7 >a >7 On that way, you take off the absolute sign and solve part by part like above.
Loser66
  • Loser66
After taking off the absolute value sign, you solve as usual, no absolute value any more.
anonymous
  • anonymous
Alright. So i won't need the bars anymore?
Loser66
  • Loser66
yup

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