Yes i do not know how to do this. I'm going out so my respond is going to be late. Can someone explain how to do this in steps not just a list of things for me to figure out. Thanks! For y = 4x + 2x2 – x3, show how to find the value for y, when x = 2. Show your work y = 2x + 2x^2+ -x^3 y3x^-1 -x^3

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Yes i do not know how to do this. I'm going out so my respond is going to be late. Can someone explain how to do this in steps not just a list of things for me to figure out. Thanks! For y = 4x + 2x2 – x3, show how to find the value for y, when x = 2. Show your work y = 2x + 2x^2+ -x^3 y3x^-1 -x^3

Mathematics
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y=2x+2x^2 - x^3 first replace all of the x's with 2 y=2(2) +2(2)^2 - 2^3 deal with your exponents y=2(2) +2(4) - 8 multiply y= 4+8 -8 simplify y= 4
Shouldn't 2(2) = 4
2(2)=4 + 2(2)^2 = 8 and -2^3 = 6

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Not getting the second 8.
?
\[y=4x+2x ^{2}-x ^{3} \] is this the problem?
Yeah, didn't notice i changed the 4 into a two sh*t
4(2)+2(2)^2 -2^3 This right?
so to go about finding for y, we sub substitute the value of x...which is 2... so\[y=4(2)+2(2)^{2}-(2)^{3}\]
we ditribute and get \[y=8+2(4)-8\]
Okay thanks i think i got it.
simplify more we get\[y=8+8-8\]..ok whats your answer?
Alright
4(2)+2(2)^2 -2^3 4(2) = 8, +2(2) =4,^2 =8, -2^3 =8, 8+8 -8
ok i what you to tell me what y=? ...8+8-8 can be simplify
y=8
correct
Thanks :)
welcome

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