I need help with a question.

- Liv1234

I need help with a question.

- Stacey Warren - Expert brainly.com

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- Liv1234

Finding the labeled lengths of a triangle. |dw:1435941173879:dw|

- Liv1234

@LegendarySadist

- anonymous

Do you have any better pictures?

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## More answers

- Liv1234

No, but I can try and draw it better.

- anonymous

I would appreciate that

- Liv1234

Okay, just a sec.

- Liv1234

|dw:1435941385187:dw|

- Liv1234

Is that better? Cause I can try again.

- anonymous

There is a tool in the draw section that allows you to make a bar, ya know

- Liv1234

Oh okay thanks. I'm fixing it now

- Liv1234

|dw:1435941515188:dw|

- Liv1234

I'm trying to find the labeled lengths.

- anonymous

And to make sure, the lengths are 4, 4, x for the first triangle and y, 1, 2 for the second?

- Liv1234

Yes.

- Liv1234

So, how would I determine the labeled lengths? That's what I'm confused about.

- Liv1234

@rvc

- rvc

as legend said

- Liv1234

Yes, those are the lengths like legend asked.

- anonymous

I feel like this is about the properties of 45-45-90 triangles and 30-60-90 triangles. The first is definitely a 45-45-90 triangle though.

- rvc

|dw:1435941970291:dw|

- Liv1234

So, how would I solve the labeled lengths though? And thanks those pictures are a lot better then mine.

- rvc

correct?

- Liv1234

And yeah, Legend is definitely correct.

- rvc

@LegendarySadist please continue :)

- anonymous

But for the first one, to find x, just apply the properties of a 45-45-90 triangle. \[\large Hypotenuse~=~Leg\sqrt{2}\]

- Liv1234

So, the square root of 2?

- anonymous

Should make it a bit clearer |dw:1435942323278:dw|

- Liv1234

Ohh okay, so 4*4=16 and then the square root of 16 which would be 4?

- anonymous

No, just \[\large x~=~4\sqrt{2}\]

- Liv1234

5.65?

- Liv1234

or 5.7 rounded?

- anonymous

Yeah, but it depends on what form they want you to leave it in. I usually would just leave it as \(4\sqrt{2}\)

- Liv1234

Okay, I have another question.

- Liv1234

Want me to open another post?

- anonymous

Are we not gonna solve for y?

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