anonymous
  • anonymous
Evaluate
Mathematics
schrodinger
  • schrodinger
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anonymous
  • anonymous
\[\sqrt{7x}\left( \sqrt{x} -7\sqrt{7}\right)\]
anonymous
  • anonymous
Show work
anonymous
  • anonymous

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anonymous
  • anonymous
@Astrophysics please help me, im dying lol this is my last question and im done with this one
Astrophysics
  • Astrophysics
Distribute the \[\sqrt{7x}\] \[\sqrt{7x} \times \sqrt{x}-\sqrt{7x} \times 7\sqrt{7}\]
Astrophysics
  • Astrophysics
\[\sqrt{7x} \times \sqrt{x} \implies \sqrt{7}\sqrt{x}\sqrt{x} \implies \sqrt{7}x\] can you do the other?
Astrophysics
  • Astrophysics
\[\sqrt{7x} \times 7\sqrt{7} \implies (1 \times 7)(\sqrt{7x}\sqrt{7}) \] you can simplify it more, I think you will be able to figure it out!
anonymous
  • anonymous
\[\sqrt{7x}*7*7*\sqrt{7}\rightarrow \sqrt{7}\sqrt{7}\sqrt{7}?\]
anonymous
  • anonymous
oh you already did it lol so what i did was obviously wrong haha
Astrophysics
  • Astrophysics
\[( 1 \times 7)(\sqrt{7x} \times \sqrt{7}) = 7\sqrt{x (7\times 7)} \implies 7\sqrt{49}\sqrt{x} \implies 7 \times 7 \sqrt{x}\] put it all together!
anonymous
  • anonymous
\[\sqrt{7x}-49\]
anonymous
  • anonymous
anonymous
  • anonymous
Am i right?
anonymous
  • anonymous
is my answer correct @mathmate ?
mathmate
  • mathmate
If the question is correct, then the answer is not! :(
Astrophysics
  • Astrophysics
No, that's not right compare your answer with the first part

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