The x-intercept of a line is -5 and the y-intercept of the line is -2. What is the equation of the line?

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- anonymous

Well, if you know that the line stops at (-5,0) and (0,-2), you can find the slope by taking the change in y over the change in x. The slope is then -2/5. Then, you take the x of one coordinate and put it into the equation, finding what must be added to get y. -2/5*0=0. To get -2, you would need to subtract 2. Therefore, b is -2. So your line, in y=mx+b form, is y=-2/5x-2. Hope this helps!

- anonymous

it does thanks so much!! i have two more problems i dont get can you help me?

- anonymous

Sorry, I was eating lunch.

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- anonymous

I can try the other problems

- anonymous

ok thanjs! i have no clue on this one
Write an equation of the line perpendicular to the given line that contains P.
y space equals space 1 fifth x space plus space 1; P(2, -7)

- anonymous

but i think this one Write the equation of the line parallel to the given line containing point P.
y space equals space 8 x space minus space 1; P(-6, 2)
is y=8x+50

- anonymous

youre supposed to use point slope from for both!

- anonymous

Okay, so for the first line you need to find the slope. A perpendicular slope is the reverse, so instead of 1 over 5 it is negative 5 over 1, or -5.

- anonymous

Do both lines in the first problem contain P??

- anonymous

yeah

- anonymous

is it -5x+3??

- anonymous

and is the second one right??

- anonymous

Yep!! Good job!! :)

- anonymous

for which one??

- anonymous

so the first and second are both right??

- anonymous

Both!!

- anonymous

thanks!!!!!!!!

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