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Well, if you know that the line stops at (-5,0) and (0,-2), you can find the slope by taking the change in y over the change in x. The slope is then -2/5. Then, you take the x of one coordinate and put it into the equation, finding what must be added to get y. -2/5*0=0. To get -2, you would need to subtract 2. Therefore, b is -2. So your line, in y=mx+b form, is y=-2/5x-2. Hope this helps!
it does thanks so much!! i have two more problems i dont get can you help me?
Sorry, I was eating lunch.
I can try the other problems
ok thanjs! i have no clue on this one Write an equation of the line perpendicular to the given line that contains P. y space equals space 1 fifth x space plus space 1; P(2, -7)
but i think this one Write the equation of the line parallel to the given line containing point P. y space equals space 8 x space minus space 1; P(-6, 2) is y=8x+50
youre supposed to use point slope from for both!
Okay, so for the first line you need to find the slope. A perpendicular slope is the reverse, so instead of 1 over 5 it is negative 5 over 1, or -5.
Do both lines in the first problem contain P??
is it -5x+3??
and is the second one right??
Yep!! Good job!! :)
for which one??
so the first and second are both right??