## anonymous one year ago The table below shows two equations: Equation 1 |2x – 3| + 5 = 4 Equation 2 |5x + 3| – 10 = 3 Which statement is true about the solution to the two equations? Equation 1 and equation 2 have no solutions. Equation 1 has no solution, and equation 2 has solutions x = 2, -3.2. The solutions to equation 1 are x = 1, 2, and equation 2 has no solution. The solutions to equation 1 are x = 1, 2, and equation 2 has solutions x = 2, -3.2.

1. amoodarya

$|2x – 3| + 5 = 4\\|2x – 3| = 4-5\\|2x – 3| =-1 <0$

2. amoodarya

$|somthing|\ge 0$

3. amoodarya

so eq 1 has no answer

4. anonymous

So its a or b

5. amoodarya

$|5x + 3| – 10 = 3\\|5x + 3| = 3+10\\|5x + 3|=13$ equation 2 has answer to solve $|somethimg|=+number\\something =\pm number\\like-this\\|u|=5 \rightarrow u=\pm 5$ can you go on ?

6. anonymous

No, sorry

7. anonymous

Got it, it's B

8. amoodarya

$|5x+3|=13\\5x+3=\pm13\\first\\5x+3=13 \rightarrow5x=13-3=10 \rightarrow x=\frac{10}{5}=2\\second\\5x+3=-13 \ \rightarrow 5x=-16 \rightarrow x=\frac{-16}{5}$