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anonymous

  • one year ago

Belinda wants to invest $1000. The table below shows the value of her investment under two different options for three different years: Number of years 1 2 3 Option 1 (amount in dollars) 1100 1210 1331 Option 2 (amount in dollars) 1100 1200 1300 Part A: What type of function, linear or exponential, can be used to describe the value of the investment after a fixed number of years using option 1 and option 2? Explain your answer. (2 points) Part B: Write one function for each option to describe the value of the investment f(n), in dollars, after n years. (4 points)

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  1. anonymous
    • one year ago
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    do you know how to do it

  2. anonymous
    • one year ago
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    @misssunshinexxoxo

  3. anonymous
    • one year ago
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    @amoodarya

  4. anonymous
    • one year ago
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    @welshfella

  5. anonymous
    • one year ago
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    can you help me

  6. welshfella
    • one year ago
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    i gotta go sorry Option 2 is linear

  7. anonymous
    • one year ago
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    ok thanks

  8. anonymous
    • one year ago
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    can some one help me

  9. anonymous
    • one year ago
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    @Tinkerbell2001

  10. anonymous
    • one year ago
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    do you know how to do this @Tinkerbell2001

  11. anonymous
    • one year ago
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    option 1 is exponential

  12. anonymous
    • one year ago
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    if you graph it the line will curve up slightly

  13. anonymous
    • one year ago
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    ok so what would the functions look like

  14. anonymous
    • one year ago
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    |dw:1435949012369:dw|

  15. anonymous
    • one year ago
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    that's what option 1 would look like

  16. anonymous
    • one year ago
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    |dw:1435949041634:dw|

  17. anonymous
    • one year ago
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    thats what 2 would look like

  18. anonymous
    • one year ago
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    ok cool but its says for put together a function and write it out do i just put those graphs as it

  19. anonymous
    • one year ago
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    you need to find the equation for the lines

  20. anonymous
    • one year ago
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    idk that part thats what i was trying to ask you about

  21. anonymous
    • one year ago
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    ok lets find the equation for option 2 first

  22. anonymous
    • one year ago
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    ok

  23. anonymous
    • one year ago
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    it will be in the form y=mx+b

  24. anonymous
    • one year ago
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    are you familiar with this?

  25. anonymous
    • one year ago
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    yes

  26. anonymous
    • one year ago
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    ok, try and solve it

  27. anonymous
    • one year ago
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    so it will look like y=1000x+1100

  28. anonymous
    • one year ago
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    yo @10115658

  29. anonymous
    • one year ago
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    sorry i was afk

  30. anonymous
    • one year ago
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    that isn't correct

  31. anonymous
    • one year ago
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    how do you find the slope?

  32. anonymous
    • one year ago
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    pick 2 points

  33. anonymous
    • one year ago
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    lets pick (1,1100) and (2,1200)

  34. anonymous
    • one year ago
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    slope is y2-y1/x2-x1

  35. anonymous
    • one year ago
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    (1200-1100)/(2-1)

  36. anonymous
    • one year ago
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    the slope is 100

  37. anonymous
    • one year ago
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    now lets find the y-intercept

  38. anonymous
    • one year ago
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    y=100x+b

  39. anonymous
    • one year ago
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    plug in one of the points for x and y

  40. anonymous
    • one year ago
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    1100=100+b

  41. anonymous
    • one year ago
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    now solve for b

  42. anonymous
    • one year ago
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    b=1000

  43. anonymous
    • one year ago
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    ok, so now we have our equation y=100x+1000

  44. anonymous
    • one year ago
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    now they want it in terms of f(n) and n so we rewrite it as f(n)=100n+1000

  45. anonymous
    • one year ago
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    that's the answer for option 2

  46. anonymous
    • one year ago
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    does that make sense?

  47. anonymous
    • one year ago
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    you there?

  48. anonymous
    • one year ago
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    yeah im here sorry

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