Belinda wants to invest $1000. The table below shows the value of her investment under two different options for three different years:
Number of years 1 2 3
Option 1 (amount in dollars) 1100 1210 1331
Option 2 (amount in dollars) 1100 1200 1300
Part A: What type of function, linear or exponential, can be used to describe the value of the investment after a fixed number of years using option 1 and option 2? Explain your answer. (2 points)
Part B: Write one function for each option to describe the value of the investment f(n), in dollars, after n years. (4 points)

- anonymous

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- anonymous

do you know how to do it

- anonymous

@misssunshinexxoxo

- anonymous

@amoodarya

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## More answers

- anonymous

@welshfella

- anonymous

can you help me

- welshfella

i gotta go sorry
Option 2 is linear

- anonymous

ok thanks

- anonymous

can some one help me

- anonymous

@Tinkerbell2001

- anonymous

do you know how to do this @Tinkerbell2001

- anonymous

option 1 is exponential

- anonymous

if you graph it the line will curve up slightly

- anonymous

ok so what would the functions look like

- anonymous

|dw:1435949012369:dw|

- anonymous

that's what option 1 would look like

- anonymous

|dw:1435949041634:dw|

- anonymous

thats what 2 would look like

- anonymous

ok cool but its says for put together a function and write it out do i just put those graphs as it

- anonymous

you need to find the equation for the lines

- anonymous

idk that part thats what i was trying to ask you about

- anonymous

ok lets find the equation for option 2 first

- anonymous

ok

- anonymous

it will be in the form y=mx+b

- anonymous

are you familiar with this?

- anonymous

yes

- anonymous

ok, try and solve it

- anonymous

so it will look like
y=1000x+1100

- anonymous

yo @10115658

- anonymous

sorry i was afk

- anonymous

that isn't correct

- anonymous

how do you find the slope?

- anonymous

pick 2 points

- anonymous

lets pick (1,1100) and (2,1200)

- anonymous

slope is y2-y1/x2-x1

- anonymous

(1200-1100)/(2-1)

- anonymous

the slope is 100

- anonymous

now lets find the y-intercept

- anonymous

y=100x+b

- anonymous

plug in one of the points for x and y

- anonymous

1100=100+b

- anonymous

now solve for b

- anonymous

b=1000

- anonymous

ok, so now we have our equation
y=100x+1000

- anonymous

now they want it in terms of f(n) and n so we rewrite it as
f(n)=100n+1000

- anonymous

that's the answer for option 2

- anonymous

does that make sense?

- anonymous

you there?

- anonymous

yeah im here sorry

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