## anonymous one year ago Write an equation of the line perpendicular to the given line that contains P. y space equals space 1 fifth x space plus space 1; P(2, -7)

1. anonymous

help me pleaase!!!

2. IrishBoy123

lmLtfy! "y space equals space 1 fifth x space plus space 1" is: $$y = \frac{1}{5}x+ 1$$ and hint: if the lines $$y = mx + c$$ and $$y = m' x + c'$$ are perp, then $$m' = -\frac{1}{m}$$ and $$m = -\frac{1}{m'}$$

3. anonymous

im osrry i still dont understand

4. IrishBoy123

5. anonymous

there is no line

6. anonymous

7. IrishBoy123

go back to your question you have a line

8. IrishBoy123

i did the Latex for you

9. IrishBoy123

no m = -1 / m' m is slope of original line m' is slope of line that is perp to original line

10. anonymous

oh right so then would it be y=1/5x+3

11. IrishBoy123

i will keep asking this :p what is the slope of your original line, the one that you posted??

12. IrishBoy123

do you know what a slope is? $$\frac{rise}{run}$$ ??

13. anonymous

1/5?

14. IrishBoy123

great so m' = -1 / m m is slope of original line m' is slope of line that is perp to original line

15. anonymous

so then it would be -1/5?

16. IrishBoy123

|dw:1435948825065:dw|

17. IrishBoy123

you're just "minusing" it. you need to invert and minus it