anonymous
  • anonymous
Write an equation of the line perpendicular to the given line that contains P. y space equals space 1 fifth x space plus space 1; P(2, -7)
Geometry
chestercat
  • chestercat
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anonymous
  • anonymous
help me pleaase!!!
IrishBoy123
  • IrishBoy123
lmLtfy! "y space equals space 1 fifth x space plus space 1" is: \(y = \frac{1}{5}x+ 1\) and hint: if the lines \(y = mx + c\) and \(y = m' x + c'\) are perp, then \(m' = -\frac{1}{m}\) and \(m = -\frac{1}{m'}\)
anonymous
  • anonymous
im osrry i still dont understand

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IrishBoy123
  • IrishBoy123
what is the gradient of your line?
anonymous
  • anonymous
there is no line
anonymous
  • anonymous
is the answer y=-1/5x-33/5??
IrishBoy123
  • IrishBoy123
go back to your question you have a line
IrishBoy123
  • IrishBoy123
i did the Latex for you
IrishBoy123
  • IrishBoy123
no m = -1 / m' m is slope of original line m' is slope of line that is perp to original line
anonymous
  • anonymous
oh right so then would it be y=1/5x+3
IrishBoy123
  • IrishBoy123
i will keep asking this :p what is the slope of your original line, the one that you posted??
IrishBoy123
  • IrishBoy123
do you know what a slope is? \(\frac{rise}{run}\) ??
anonymous
  • anonymous
1/5?
IrishBoy123
  • IrishBoy123
great so m' = -1 / m m is slope of original line m' is slope of line that is perp to original line
anonymous
  • anonymous
so then it would be -1/5?
IrishBoy123
  • IrishBoy123
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IrishBoy123
  • IrishBoy123
you're just "minusing" it. you need to invert and minus it

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