Which of the following systems of inequalities would have no solution? Select one: a. y > 2x + 1 y < -3x b. y > 3x + 1 y < 3x + 8 c. y > 1/2x + 8 y < -2x -2 d. y < 3x + 1 y > 3x + 8

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Which of the following systems of inequalities would have no solution? Select one: a. y > 2x + 1 y < -3x b. y > 3x + 1 y < 3x + 8 c. y > 1/2x + 8 y < -2x -2 d. y < 3x + 1 y > 3x + 8

Mathematics
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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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C
lol
Lol. C is always the correct answer, but not this time.

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Other answers:

You could graph it the 2 equations using https://www.desmos.com/calculator and see which ones don't have any shaded area common to both equations.
Don't let the less than greater than confuse you in these questions, set it up as you would regularly with a equation of a line y = mx+b just with a few rules, which can be found here: https://www.mathsisfun.com/algebra/inequality-properties.html
This is for answer choice C https://www.desmos.com/calculator/s6zvheaiy4 |dw:1436143999795:dw|
You can see it has a shaded area (which is common to both) that shows it does have a solution. Which answer choice gives you a graph that has no common shaded area?

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