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anonymous
 one year ago
Find the area of the parallelogram with corner \( P_1\) and adjacent sides \( P_1 P_2\) and \( P_1 P_3\)
\( P_1 =(1,2,0)\), \( P_2= (1,4,2)\), \( P_3=(3,1,3)\)
If u and v are nonzero vectors in space, then\( \ u\times v\\) is the area of the parallelogram having u and v as adjacent sides.
u = \( P_1\space P_2 = 2i+2j+2k\)
How is u equaling that? I thought we times the P1 and p2 but it does not seem to be that way...
anonymous
 one year ago
Find the area of the parallelogram with corner \( P_1\) and adjacent sides \( P_1 P_2\) and \( P_1 P_3\) \( P_1 =(1,2,0)\), \( P_2= (1,4,2)\), \( P_3=(3,1,3)\) If u and v are nonzero vectors in space, then\( \ u\times v\\) is the area of the parallelogram having u and v as adjacent sides. u = \( P_1\space P_2 = 2i+2j+2k\) How is u equaling that? I thought we times the P1 and p2 but it does not seem to be that way...

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I can figure out the rest but not sure how they got u

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Find the area of the parallelogram with corner \(P_1\) and adjacent sides\( P1 P2\) and \( P1 P3 \) \( P_1 =(1,2,0) \)\( P_2= (1,4,2) \) \(P_3=(3,1,3) \) If u and v are nonzero vectors in space, then\( \u\times v\\) is the area of the parallelogram having u and v as adjacent side Find the two adjacent sides of this parallelogram . \( u =P_1\space P_2 = 2i+2j+2k \) \( v =P_1\space P_3 = 4i3j+3k \) How are they getting u and V up above?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0@Gunboss is that how old you are? :D

nincompoop
 one year ago
Best ResponseYou've already chosen the best response.0try drawing/graphing it

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Nope that will not help but I think I just thought of something, HAHAHA and it might work. BRB let going to go see

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Nope, that was not it........

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0AH I think I got it this time

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I GOT IT!!!!! I LOVE IT I LOVE IT \[\huge u= (x_2x_1)+ (y_2y_1)+(z_2z_1) \] \[ \huge u = (i_2i_1)+ (j_2j_1)+(k_2k_1) \] \[ \huge u = (11)i+ (42)j+(20)k \] \[ \huge u = 2i+ 2j+2k \]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I can finish now :) This stuff is FUN :D

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0After it is all done the \( \ u \times v \ = 2\sqrt{86} \) Yep got it. Thanks to all that came to look at my problem.
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