anonymous
  • anonymous
.
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
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anonymous
  • anonymous
I'm not sure sorry.
anonymous
  • anonymous
Np
princeharryyy
  • princeharryyy
x^2 + 4x +x +4 =0 x(x+4) + 1(x+4) =0 (x+1)(x+4)=0 =>x=-1,-4

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anonymous
  • anonymous
How do we define radicand?
princeharryyy
  • princeharryyy
yeah
anonymous
  • anonymous
Radicand is the discriminate or b^2 - 4ac and @princeharryyy please do not solely give answers
anonymous
  • anonymous
So If the discriminant is positive, there are two real roots. If it is zero, there is one real root (a double root). And if the discriminant is negative, there are two imaginary roots and no real roots
campbell_st
  • campbell_st
the radicand is the discriminant so you need to use for a quadratic \[ax^2 + bx + c = 0\] the discriminant is \[\Delta = b^2 - 4ac\]
princeharryyy
  • princeharryyy
tnks, i'm not in mood as well @whatdoesthismean by the way discriminate means (The value you want to take the root of)
princeharryyy
  • princeharryyy
radical*
anonymous
  • anonymous
By plugging a b and c, you can find the answer to A as it is asking for the DESCRIPTION of the solutions, not the solutions itself
campbell_st
  • campbell_st
so for the other parts.. Part B the quadratic can be factored Pact C use the general quadratic formula
anonymous
  • anonymous
as i said before, the descriptions are as follows'\; So If the discriminant is positive, there are two real roots. If it is zero, there is one real root (a double root). And if the discriminant is negative, there are two imaginary roots and no real roots
anonymous
  • anonymous
Agreed @campbell_st
campbell_st
  • campbell_st
and when you do part A you have a = 1, b = 5 and c = 4 and if the discriminant is positive there are 2 options (a) the discriminant is a sqiare number, 1, 4, 9, 16.... then the roots are real, rational and unequal (b) is the discriminant is not a square number e.g. 3, 7, 10, 15, etc the roots are real, irrational and unequal
anonymous
  • anonymous
No, youre supposed to try and use the information and solve it
campbell_st
  • campbell_st
ok... you need \[\Delta = b^2 - 4\times a \times c\] the equation have a = 1, b = 5 and c = 4 plug them in post the answer you get..
campbell_st
  • campbell_st
well \[\Delta = 5^2 - 4 \times 1 \times 4\] what is the value of the calculation
campbell_st
  • campbell_st
ummm can you recheck it \[\Delta = 25 - 16\]
campbell_st
  • campbell_st
ummmm I think \[\Delta = 25 - 16~~~means~~~~\Delta = 9\] so based on the solution being >0 and a square number, what type of solutions do you have...?

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