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anonymous

  • one year ago

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  1. anonymous
    • one year ago
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    I'm not sure sorry.

  2. anonymous
    • one year ago
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    Np

  3. princeharryyy
    • one year ago
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    x^2 + 4x +x +4 =0 x(x+4) + 1(x+4) =0 (x+1)(x+4)=0 =>x=-1,-4

  4. anonymous
    • one year ago
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    How do we define radicand?

  5. princeharryyy
    • one year ago
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    yeah

  6. anonymous
    • one year ago
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    Radicand is the discriminate or b^2 - 4ac and @princeharryyy please do not solely give answers

  7. anonymous
    • one year ago
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    So If the discriminant is positive, there are two real roots. If it is zero, there is one real root (a double root). And if the discriminant is negative, there are two imaginary roots and no real roots

  8. campbell_st
    • one year ago
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    the radicand is the discriminant so you need to use for a quadratic \[ax^2 + bx + c = 0\] the discriminant is \[\Delta = b^2 - 4ac\]

  9. princeharryyy
    • one year ago
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    tnks, i'm not in mood as well @whatdoesthismean by the way discriminate means (The value you want to take the root of)

  10. princeharryyy
    • one year ago
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    radical*

  11. anonymous
    • one year ago
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    By plugging a b and c, you can find the answer to A as it is asking for the DESCRIPTION of the solutions, not the solutions itself

  12. campbell_st
    • one year ago
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    so for the other parts.. Part B the quadratic can be factored Pact C use the general quadratic formula

  13. anonymous
    • one year ago
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    as i said before, the descriptions are as follows'\; So If the discriminant is positive, there are two real roots. If it is zero, there is one real root (a double root). And if the discriminant is negative, there are two imaginary roots and no real roots

  14. anonymous
    • one year ago
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    Agreed @campbell_st

  15. campbell_st
    • one year ago
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    and when you do part A you have a = 1, b = 5 and c = 4 and if the discriminant is positive there are 2 options (a) the discriminant is a sqiare number, 1, 4, 9, 16.... then the roots are real, rational and unequal (b) is the discriminant is not a square number e.g. 3, 7, 10, 15, etc the roots are real, irrational and unequal

  16. anonymous
    • one year ago
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    No, youre supposed to try and use the information and solve it

  17. campbell_st
    • one year ago
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    ok... you need \[\Delta = b^2 - 4\times a \times c\] the equation have a = 1, b = 5 and c = 4 plug them in post the answer you get..

  18. campbell_st
    • one year ago
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    well \[\Delta = 5^2 - 4 \times 1 \times 4\] what is the value of the calculation

  19. campbell_st
    • one year ago
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    ummm can you recheck it \[\Delta = 25 - 16\]

  20. campbell_st
    • one year ago
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    ummmm I think \[\Delta = 25 - 16~~~means~~~~\Delta = 9\] so based on the solution being >0 and a square number, what type of solutions do you have...?

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