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anonymous
 one year ago
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anonymous
 one year ago
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princeharryyy
 one year ago
Best ResponseYou've already chosen the best response.0x^2 + 4x +x +4 =0 x(x+4) + 1(x+4) =0 (x+1)(x+4)=0 =>x=1,4

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0How do we define radicand?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Radicand is the discriminate or b^2  4ac and @princeharryyy please do not solely give answers

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0So If the discriminant is positive, there are two real roots. If it is zero, there is one real root (a double root). And if the discriminant is negative, there are two imaginary roots and no real roots

campbell_st
 one year ago
Best ResponseYou've already chosen the best response.0the radicand is the discriminant so you need to use for a quadratic \[ax^2 + bx + c = 0\] the discriminant is \[\Delta = b^2  4ac\]

princeharryyy
 one year ago
Best ResponseYou've already chosen the best response.0tnks, i'm not in mood as well @whatdoesthismean by the way discriminate means (The value you want to take the root of)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0By plugging a b and c, you can find the answer to A as it is asking for the DESCRIPTION of the solutions, not the solutions itself

campbell_st
 one year ago
Best ResponseYou've already chosen the best response.0so for the other parts.. Part B the quadratic can be factored Pact C use the general quadratic formula

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0as i said before, the descriptions are as follows'\; So If the discriminant is positive, there are two real roots. If it is zero, there is one real root (a double root). And if the discriminant is negative, there are two imaginary roots and no real roots

campbell_st
 one year ago
Best ResponseYou've already chosen the best response.0and when you do part A you have a = 1, b = 5 and c = 4 and if the discriminant is positive there are 2 options (a) the discriminant is a sqiare number, 1, 4, 9, 16.... then the roots are real, rational and unequal (b) is the discriminant is not a square number e.g. 3, 7, 10, 15, etc the roots are real, irrational and unequal

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0No, youre supposed to try and use the information and solve it

campbell_st
 one year ago
Best ResponseYou've already chosen the best response.0ok... you need \[\Delta = b^2  4\times a \times c\] the equation have a = 1, b = 5 and c = 4 plug them in post the answer you get..

campbell_st
 one year ago
Best ResponseYou've already chosen the best response.0well \[\Delta = 5^2  4 \times 1 \times 4\] what is the value of the calculation

campbell_st
 one year ago
Best ResponseYou've already chosen the best response.0ummm can you recheck it \[\Delta = 25  16\]

campbell_st
 one year ago
Best ResponseYou've already chosen the best response.0ummmm I think \[\Delta = 25  16~~~means~~~~\Delta = 9\] so based on the solution being >0 and a square number, what type of solutions do you have...?
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