anonymous
  • anonymous
help please
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
With?
anonymous
  • anonymous
1 Attachment
campbell_st
  • campbell_st
well you can use the law of cosines to check do you know how to use it..?

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anonymous
  • anonymous
no i dont :(
jennyrlz
  • jennyrlz
sec let me see what i can remeber :)
anonymous
  • anonymous
k
anonymous
  • anonymous
http://mathworld.wolfram.com/LawofCosines.html
anonymous
  • anonymous
im to lazy to draw the abc triangle lol, but that explains the law of cosines well
campbell_st
  • campbell_st
the law of cosines says \[Cos(A) = \frac{b^2 = c^2 - a^2}{2bc}\] does that help
campbell_st
  • campbell_st
you have a = 5.3, b = 7 and c = 4... plug them in and post the answer you get
campbell_st
  • campbell_st
oops should read \[\cos(A) = \frac{b^2 + c^2 - a^2}{2bc}\]
jennyrlz
  • jennyrlz
^
anonymous
  • anonymous
oh wait is it true?
jennyrlz
  • jennyrlz
ill leave it to him, he knows what he is doing :)
jennyrlz
  • jennyrlz
oh he left...
jennyrlz
  • jennyrlz
well why do you think it is true?
jennyrlz
  • jennyrlz
he did the "hard" part the rest is algebra
campbell_st
  • campbell_st
well you need to find the angle measure using the law of cosines to see if its true or not
campbell_st
  • campbell_st
an alternative solution is to google a triangle solver put in the 3 sides and then look at the angles that are calculated
anonymous
  • anonymous
which law of cosine should i use
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jennyrlz
  • jennyrlz
if only i wouldve thought of this when i was taking pre-calc...
campbell_st
  • campbell_st
use the one I posted above
anonymous
  • anonymous
how do i use it....do i sub
campbell_st
  • campbell_st
and look for the measures that match the labels a, b and c
campbell_st
  • campbell_st
a = 5.3 b = 7 and c = 4 like this \[cos(\theta) = \frac{7^2 + 4^2 - 5.3^2}{2 \times 7 \times 4}\]
anonymous
  • anonymous
doin the math.....
anonymous
  • anonymous
\[\cos \theta \frac{ 49+16-28.09 }{66 }\] thats what i have so far
anonymous
  • anonymous
is it right
anonymous
  • anonymous
so far
campbell_st
  • campbell_st
well I think the denominator is 56
campbell_st
  • campbell_st
2 x 4 x 7 = 56
anonymous
  • anonymous
oh yea
anonymous
  • anonymous
wait so it is true?
campbell_st
  • campbell_st
not yet, if you do the calculation you'll find \[\cos(\theta) = 0.659107\] so to find the angle, using a calculator its \[\theta = \cos^{-1}(0.659107)\]
anonymous
  • anonymous
i got 0.79053943 ? how do i punch this equation in a calculator

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