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anonymous
 one year ago
Need help with simplifying roots (medal and fan)
anonymous
 one year ago
Need help with simplifying roots (medal and fan)

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0\[(\frac{ \sqrt{2} }{ 2 } \times \frac{ 1 }{ 2 })  (\frac{ \sqrt{2} }{ 2} \times \frac{ \sqrt{3} }{ 2 })\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0The answer is: \[\frac{ 1 }{ 4 }(\sqrt{2}+\sqrt{6})\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I don't understand how this is the answer. I must be doing something very wrong. Here's my work: \[\frac{ \sqrt{2} }{ 4 }\frac{ \sqrt{6} }{ 4 }\] Then: \[\frac{ \sqrt{2} \sqrt{6}}{ 4 }\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0\(\bf \left(\cfrac{ \sqrt{2} }{ 2 } \times \cfrac{ 1 }{ 2 }\right) \left( \cfrac{ \sqrt{2} }{ 2} \times \cfrac{ \sqrt{3} }{ 2 } \right)\implies \cfrac{ \sqrt{2} \sqrt{6}}{ 4 } \\ \quad \\ \cfrac{\sqrt{2}}{4}+\cfrac{\sqrt{6}}{4}\implies \left( \cfrac{1}{4}\sqrt{2} \right)+\left( \cfrac{1}{4}\sqrt{6} \right)\impliedby \textit{common factor} \\ \quad \\ \cfrac{1}{4}\left( \sqrt{2}+\sqrt{6} \right)\)
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