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anonymous
 one year ago
Please can somebody help me? i completely forgot how to do this D:
Rewrite the expression by factoring out (y+6)
5y^2(y+6)7(y+6)
anonymous
 one year ago
Please can somebody help me? i completely forgot how to do this D: Rewrite the expression by factoring out (y+6) 5y^2(y+6)7(y+6)

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0\(\bf 5y^2({\color{blue}{ y+6 }} )7({\color{blue}{ y+6 }} )\implies ({\color{blue}{ y+6 }} )[\square ?\square ?]\)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0i dont understand u.u what is the answer? @jdoe0001

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0lemme put it this way do you know how to do common facotoring?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0say.. how factor say for example abc + abd = ?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0i really dont get, its just it has been a long time since i do this, and now i have to do a math class online but im really struggling with this question :( @jdoe0001

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0well.. do you know what a "factor" is?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0yeah, numbers you multiply to get other numbers right?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0well values or objects really numbers just happen to be numeric objects so a variable is also an object so.... common factor is a "factor" that is common to all terms so... what do you think about abc + abd = ? or (a * b * c) + (a * b * d) < what's the common factor(s) ?

DecentNabeel
 one year ago
Best ResponseYou've already chosen the best response.25y^2(y+6)7(y+6) factor out (y+6) (y+6)(5y^27)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0nice, thank you so much

DecentNabeel
 one year ago
Best ResponseYou've already chosen the best response.2welcome @Rickyvalencia
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