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muscrat123
 one year ago
A running track in the shape of an oval is shown. The ends of the track form semicircles.
What is the perimeter of the inside of the track?
(π = 3.14)
392.00 m
372.22 m
444.44 m
588.88 m
muscrat123
 one year ago
A running track in the shape of an oval is shown. The ends of the track form semicircles. What is the perimeter of the inside of the track? (π = 3.14) 392.00 m 372.22 m 444.44 m 588.88 m

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muscrat123
 one year ago
Best ResponseYou've already chosen the best response.1@misssunshinexxoxo @Mehek14

Mehek14
 one year ago
Best ResponseYou've already chosen the best response.2first we find the perimeter of the 2 semicircles

Mehek14
 one year ago
Best ResponseYou've already chosen the best response.2the formula for the perimeter of a semicircle is \(\dfrac{1}{2}πd\)

Mehek14
 one year ago
Best ResponseYou've already chosen the best response.2so \(\dfrac{1}{2}*3.14*46= 72.22\)

Mehek14
 one year ago
Best ResponseYou've already chosen the best response.2you have 2 semicircles so \(72.22*2= 144.44\)

Mehek14
 one year ago
Best ResponseYou've already chosen the best response.2no add the length of the 2 sides 150+150 = 300 \(300+144.44=444.44\)

muscrat123
 one year ago
Best ResponseYou've already chosen the best response.1srry my mom called me @Mehek14

Mehek14
 one year ago
Best ResponseYou've already chosen the best response.2I solved it for you look
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