muscrat123
  • muscrat123
A running track in the shape of an oval is shown. The ends of the track form semicircles. What is the perimeter of the inside of the track? (π = 3.14) 392.00 m 372.22 m 444.44 m 588.88 m
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
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muscrat123
  • muscrat123
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muscrat123
  • muscrat123
@misssunshinexxoxo @Mehek14
muscrat123
  • muscrat123
@Mehek14

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More answers

Mehek14
  • Mehek14
first we find the perimeter of the 2 semicircles
muscrat123
  • muscrat123
92? @Mehek14
Mehek14
  • Mehek14
the formula for the perimeter of a semicircle is \(\dfrac{1}{2}πd\)
Mehek14
  • Mehek14
so \(\dfrac{1}{2}*3.14*46= 72.22\)
muscrat123
  • muscrat123
@misssunshinexxoxo
Mehek14
  • Mehek14
you have 2 semicircles so \(72.22*2= 144.44\)
muscrat123
  • muscrat123
ok
Mehek14
  • Mehek14
no add the length of the 2 sides 150+150 = 300 \(300+144.44=444.44\)
Mehek14
  • Mehek14
now*
muscrat123
  • muscrat123
srry my mom called me @Mehek14
muscrat123
  • muscrat123
what do i do?
Mehek14
  • Mehek14
I solved it for you look
muscrat123
  • muscrat123
srry!
muscrat123
  • muscrat123
thx @Mehek14
Mehek14
  • Mehek14
yw

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