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muscrat123

  • one year ago

A running track in the shape of an oval is shown. The ends of the track form semicircles. What is the perimeter of the inside of the track? (π = 3.14) 392.00 m 372.22 m 444.44 m 588.88 m

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  1. muscrat123
    • one year ago
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  2. muscrat123
    • one year ago
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    @misssunshinexxoxo @Mehek14

  3. muscrat123
    • one year ago
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    @Mehek14

  4. Mehek14
    • one year ago
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    first we find the perimeter of the 2 semicircles

  5. muscrat123
    • one year ago
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    92? @Mehek14

  6. Mehek14
    • one year ago
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    the formula for the perimeter of a semicircle is \(\dfrac{1}{2}πd\)

  7. Mehek14
    • one year ago
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    so \(\dfrac{1}{2}*3.14*46= 72.22\)

  8. muscrat123
    • one year ago
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    @misssunshinexxoxo

  9. Mehek14
    • one year ago
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    you have 2 semicircles so \(72.22*2= 144.44\)

  10. muscrat123
    • one year ago
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    ok

  11. Mehek14
    • one year ago
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    no add the length of the 2 sides 150+150 = 300 \(300+144.44=444.44\)

  12. Mehek14
    • one year ago
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    now*

  13. muscrat123
    • one year ago
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    srry my mom called me @Mehek14

  14. muscrat123
    • one year ago
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    what do i do?

  15. Mehek14
    • one year ago
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    I solved it for you look

  16. muscrat123
    • one year ago
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    srry!

  17. muscrat123
    • one year ago
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    thx @Mehek14

  18. Mehek14
    • one year ago
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    yw

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