anonymous
  • anonymous
Factor 3x^2y^2 -xy^2-2y^2 Show your work
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
you know that ^ means exponent right not multiply
anonymous
  • anonymous
@nincompoop
anonymous
  • anonymous
Yeah I need help solving it with steps

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welshfella
  • welshfella
Take out the GCF y^2
jdoe0001
  • jdoe0001
\(\bf 3x^2y^2 -xy^2-2y^2\implies 3{\color{blue}{ x}}x{\color{blue}{ yy}}-x{\color{blue}{ yy}}-2{\color{blue}{ yy}}\) take the common factor
anonymous
  • anonymous
I'm really confused
jdoe0001
  • jdoe0001
hmm \(\bf 3x^2y^2 -xy^2-2y^2\implies 3{x}x{\color{blue}{ yy}}-x{\color{blue}{ yy}}-2{\color{blue}{ yy}}\) rather
anonymous
  • anonymous
I don't even know where to start
welshfella
  • welshfella
y^2(3x^2 - x - 2)
anonymous
  • anonymous
Yes could you please show me the steps
DecentNabeel
  • DecentNabeel
\[\mathrm{Factor}\:-2y^2+3x^2y^2-xy^2:\quad y^2\left(x-1\right)\left(3x+2\right)\]
jdoe0001
  • jdoe0001
hmm do you know how to take a common factor?
anonymous
  • anonymous
Nope
jdoe0001
  • jdoe0001
well.. then you may want to cover that firstly then
DecentNabeel
  • DecentNabeel
3x^2y^2 -xy^2-2y^2 take out y^2 \[=y^2\left(3x^2-x-2\right)\] \[\mathrm{Factor}\:3x^2-x-2:\quad \left(x-1\right)\left(3x+2\right)\] \[=y^2\left(x-1\right)\left(3x+2\right)\]
anonymous
  • anonymous
3x^2y^2-xy^2-2y^2 -2y^2 +3x^2y^2-xy^2
anonymous
  • anonymous
I just want to put this all together so it won't be difficult for you for your reference: Pulling out like terms : 5.1 Pull out like factors : 3x2y2 - xy2 - 2y2 = y2 • (3x2 - x - 2) Trying to factor by splitting the middle term 5.2 Factoring 3x2 - x - 2 The first term is, 3x2 its coefficient is 3 . The middle term is, -x its coefficient is -1 . The last term, "the constant", is -2 Step-1 : Multiply the coefficient of the first term by the constant 3 • -2 = -6 Step-2 : Find two factors of -6 whose sum equals the coefficient of the middle term, which is -1 . -6 + 1 = -5 -3 + 2 = -1 That's it Step-3 : Rewrite the polynomial splitting the middle term using the two factors found in step 2 above, -3 and 2 3x2 - 3x + 2x - 2 Step-4 : Add up the first 2 terms, pulling out like factors : 3x • (x-1) Add up the last 2 terms, pulling out common factors : 2 • (x-1) Step-5 : Add up the four terms of step 4 : (3x+2) • (x-1) Which is the desired factorization
anonymous
  • anonymous
Thank you so much! Could you help on another
anonymous
  • anonymous
Factor x^2+6x+9
DecentNabeel
  • DecentNabeel
\[\mathrm{Factor}\:x^2+6x+9:\quad \left(x+3\right)^2\]
anonymous
  • anonymous
1 Q per thread pls.
anonymous
  • anonymous
& Try tipping those who help you out by rewarding them w/ a medal by clicking that 'best response' button.
anonymous
  • anonymous
Ok thanks so muc!
anonymous
  • anonymous
\(\Large\rm\color{darkviolet}{\sideset{_\star~^\star}{~~_\star~^\star}{_\star}\hspace{-56pt}\color{blueviolet}{\overset{^\star~~~_\star~~~_\star~~~^\star~~~_\star~~~^\star~~~^\star}{^\star~^\star~~~ \star~~~~_\star~\star~_\star~~~^\star}\hspace{-35pt}}\color{bluepurple}{\underset{^\star~~~^\star~~~\star~~~_\star~~~\star~~~^\star~~~_\star~~~}{\star}}}\hspace{96pt}\Large\rm\color{darkviolet}{\sideset{_\star~^\star}{~~~~~~^\star}{_\star}\hspace{-129pt}\color{blueviolet}{\overset{^\star~~~_\star~~~_\star~~~^\star~~~_\star~~~^\star~~~^\star}{^\star~^\star~~~ \star~^\star~~\star~~~_\star~~~^\star}\hspace{-159pt}}\color{bluepurple}{\underset{^\star~~~^\star~~~\star~~~_\star~~~\star~~~^\star~~~_\star~~~}{\star}}}\hspace{-165pt}\LARGE\rlap{\it\color{red}{W}\color{orange}{e}\color{gold}{l}\color{lime}{c}\color{blue}{o}\color{blueviolet}{m}\color{purple}{e}\color{orchid}{~t}\color{magenta}{o}\color{red}{~O}\color{orange}{p}\color{gold}{e}\color{lime}{n}\color{cyan}{S}\color{blue}{t}\color{blueviolet}{u}\color{purple}{d}\color{orchid}{y}\color{magenta}{!}}{\hspace{-1.5pt}\it\color{black}{Welcome~to~OpenStudy!}}\) \(\it\color{charcoal}{~~~~Please~be~sure~to~read~OpenStudy's~terms~listed~within~the~following~links:}\) \(~\hspace{1.5pt}\large\color{red}{_✧~}\huge\color{orange}{^✧~}\normalsize\color{gold}{✧~~}\Large\color{blue}{/)}\LARGE\color{blue}{_∧}\Large\color{blue}{/)~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~}\hspace{-3.5pt}\Large\color{blueviolet}{/)}\LARGE\color{blueviolet}{_∧}\Large\color{blueviolet}{/)~~~~}\hspace{-10pt}\large\color{gold}{^✧}\LARGE\color{orange}{_✧}\huge\color{yellow}{^✧}\)\(~~\Large\color{red}{~~_✧~~}\large\rm\color{blue}{O(}\Large\color{blue}{^}\color{blue}{_ヮ}\hspace{-2pt}\Large\color{blue}{^}\hspace{-2pt}\color{blue}{)o}\hspace{160pt}\Large\rm\color{blueviolet}{o(}\Large\hspace{-3pt}\color{blueviolet}{^}\color{blueviolet}{_ヮ}\hspace{-2pt}\Large\color{blueviolet}{^~}\hspace{-3pt}\large\color{blueviolet}{)O}\small\color{orange}{~_✧}\Large\color{gold}{~~^✧}\hspace{-235.7pt}\underset{\href{https:///openstudy.com/terms-and-conditions}{\hspace{0pt}\LARGE\it{\color{red}{\bigstar~T}}\color{orange}{e}\color{gold}{r}\color{lime}{m}\color{cyan}{s}\color{blue}{~a}\color{blueviolet}{n}\color{purple}{d}\color{orchid}{~C}\color{magenta}{o}\color{pink}{n}\color{red}{d}\color{orange}{i}\color{gold}{t}\color{lime}{i}\color{cyan}{o}\color{blue}{n}\color{blueviolet}{s}\color{red}{~\bigstar}}}{{\href{https:///openstudy.com/code-of-conduct}{\hspace{5.5pt}\large\it{\color{red}{\bigstar~C}}\color{orange}{o}\color{gold}{d}\color{lime}{e~}\color{cyan}{o}\color{blue}{f~}\color{blueviolet}{C}\color{purple}{o}\color{orchid}{n}\color{magenta}{d}\color{pink}{u}\color{red}{c}\color{orange}{t}\color{red}{~\bigstar}}}}\) \(~\small\color{red}{~~~~~~~~_✧~~~~}\hspace{0pt}\large\rm\color{blue}{O(")(")~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~}\hspace{0pt}\large\rm\color{blueviolet}{(")(")O}\small\color{red}{~~~~~~✧}\) \(\Large\color{green}{~~~~~⌒⌒⌒⌒⌒⌒⌒⌒⌒⌒⌒⌒⌒⌒⌒⌒⌒⌒⌒⌒⌒⌒⌒⌒⌒⌒⌒⌒⌒⌒⌒⌒⌒⌒}\)
anonymous
  • anonymous
@DecentNabeel x^2 +3x +3x +9
anonymous
  • anonymous
What's after
DecentNabeel
  • DecentNabeel
\[\mathrm{Simplify}\:x^2+3x+3x+9:\quad x^2+6x+9\]
anonymous
  • anonymous
(X+3)(x+3)
DecentNabeel
  • DecentNabeel
\[\mathrm{Simplify}\:\left(x+3\right)\left(x+3\right):\quad \left(x+3\right)^2\]
DecentNabeel
  • DecentNabeel
Happy @kayleeq :)
anonymous
  • anonymous
Wait what happened I'm sorry
anonymous
  • anonymous
Factor x^2 -25
DecentNabeel
  • DecentNabeel
(x-5)(x+5)
anonymous
  • anonymous
Is that all the steps
anonymous
  • anonymous
Is a common factor for all of the x^2
DecentNabeel
  • DecentNabeel
x^2 -25 this formula a^2-b^2=(a-b)(a+b) x^2-5^2=(x-5)(x+5)
anonymous
  • anonymous
Is that all of the steps though I'm so confused
DecentNabeel
  • DecentNabeel
tell me why confused
DecentNabeel
  • DecentNabeel
\[x^2-25=\left(x+5\right)\left(x-5\right)\]
anonymous
  • anonymous
Is that the steps I don't know how to do this I've been at it for forever
DecentNabeel
  • DecentNabeel
you know a^2-b^2=(a-b)(a+b)
DecentNabeel
  • DecentNabeel
do you know this
anonymous
  • anonymous
What are the steps can you please show me with the actual numbers please yes but is am so conus fed with this question please help me
DecentNabeel
  • DecentNabeel
x^2 -25 use this formula:a^2-b^2=(a-b)(a+b): 25=5^2 x^2-5^2=(x-5)(x+5)
DecentNabeel
  • DecentNabeel
MATHEMATICAL FORMULAE Algebra 1. (a + b)2 = a2 + 2ab + b2; a2 + b2 = (a + b)2 − 2ab 2. (a − b)2 = a2 − 2ab + b2; a2 + b2 = (a − b)2 + 2ab 3. (a + b + c)2 = a2 + b2 + c2 + 2(ab + bc + ca) 4. (a + b)3 = a3 + b3 + 3ab(a + b); a3 + b3 = (a + b)3 − 3ab(a + b) 5. (a − b)3 = a3 − b3 − 3ab(a − b); a3 − b3 = (a − b)3 + 3ab(a − b) 6. a2 − b2 = (a + b)(a − b)
anonymous
  • anonymous
Oooooooooo ok I got that see I just needed some explaination now only the second and third polynomial share a common factor is that correct it is x^2
DecentNabeel
  • DecentNabeel
yes
anonymous
  • anonymous
Ok thank you sooooooooo much
DecentNabeel
  • DecentNabeel
welcome @kayleeq

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