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anonymous
 one year ago
Factor 3x^2y^2 xy^22y^2
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anonymous
 one year ago
Factor 3x^2y^2 xy^22y^2 Show your work

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0you know that ^ means exponent right not multiply

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Yeah I need help solving it with steps

welshfella
 one year ago
Best ResponseYou've already chosen the best response.0Take out the GCF y^2

jdoe0001
 one year ago
Best ResponseYou've already chosen the best response.0\(\bf 3x^2y^2 xy^22y^2\implies 3{\color{blue}{ x}}x{\color{blue}{ yy}}x{\color{blue}{ yy}}2{\color{blue}{ yy}}\) take the common factor

jdoe0001
 one year ago
Best ResponseYou've already chosen the best response.0hmm \(\bf 3x^2y^2 xy^22y^2\implies 3{x}x{\color{blue}{ yy}}x{\color{blue}{ yy}}2{\color{blue}{ yy}}\) rather

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I don't even know where to start

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Yes could you please show me the steps

DecentNabeel
 one year ago
Best ResponseYou've already chosen the best response.0\[\mathrm{Factor}\:2y^2+3x^2y^2xy^2:\quad y^2\left(x1\right)\left(3x+2\right)\]

jdoe0001
 one year ago
Best ResponseYou've already chosen the best response.0hmm do you know how to take a common factor?

jdoe0001
 one year ago
Best ResponseYou've already chosen the best response.0well.. then you may want to cover that firstly then

DecentNabeel
 one year ago
Best ResponseYou've already chosen the best response.03x^2y^2 xy^22y^2 take out y^2 \[=y^2\left(3x^2x2\right)\] \[\mathrm{Factor}\:3x^2x2:\quad \left(x1\right)\left(3x+2\right)\] \[=y^2\left(x1\right)\left(3x+2\right)\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.03x^2y^2xy^22y^2 2y^2 +3x^2y^2xy^2

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I just want to put this all together so it won't be difficult for you for your reference: Pulling out like terms : 5.1 Pull out like factors : 3x2y2  xy2  2y2 = y2 • (3x2  x  2) Trying to factor by splitting the middle term 5.2 Factoring 3x2  x  2 The first term is, 3x2 its coefficient is 3 . The middle term is, x its coefficient is 1 . The last term, "the constant", is 2 Step1 : Multiply the coefficient of the first term by the constant 3 • 2 = 6 Step2 : Find two factors of 6 whose sum equals the coefficient of the middle term, which is 1 . 6 + 1 = 5 3 + 2 = 1 That's it Step3 : Rewrite the polynomial splitting the middle term using the two factors found in step 2 above, 3 and 2 3x2  3x + 2x  2 Step4 : Add up the first 2 terms, pulling out like factors : 3x • (x1) Add up the last 2 terms, pulling out common factors : 2 • (x1) Step5 : Add up the four terms of step 4 : (3x+2) • (x1) Which is the desired factorization

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Thank you so much! Could you help on another

DecentNabeel
 one year ago
Best ResponseYou've already chosen the best response.0\[\mathrm{Factor}\:x^2+6x+9:\quad \left(x+3\right)^2\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0& Try tipping those who help you out by rewarding them w/ a medal by clicking that 'best response' button.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0\(\Large\rm\color{darkviolet}{\sideset{_\star~^\star}{~~_\star~^\star}{_\star}\hspace{56pt}\color{blueviolet}{\overset{^\star~~~_\star~~~_\star~~~^\star~~~_\star~~~^\star~~~^\star}{^\star~^\star~~~ \star~~~~_\star~\star~_\star~~~^\star}\hspace{35pt}}\color{bluepurple}{\underset{^\star~~~^\star~~~\star~~~_\star~~~\star~~~^\star~~~_\star~~~}{\star}}}\hspace{96pt}\Large\rm\color{darkviolet}{\sideset{_\star~^\star}{~~~~~~^\star}{_\star}\hspace{129pt}\color{blueviolet}{\overset{^\star~~~_\star~~~_\star~~~^\star~~~_\star~~~^\star~~~^\star}{^\star~^\star~~~ \star~^\star~~\star~~~_\star~~~^\star}\hspace{159pt}}\color{bluepurple}{\underset{^\star~~~^\star~~~\star~~~_\star~~~\star~~~^\star~~~_\star~~~}{\star}}}\hspace{165pt}\LARGE\rlap{\it\color{red}{W}\color{orange}{e}\color{gold}{l}\color{lime}{c}\color{blue}{o}\color{blueviolet}{m}\color{purple}{e}\color{orchid}{~t}\color{magenta}{o}\color{red}{~O}\color{orange}{p}\color{gold}{e}\color{lime}{n}\color{cyan}{S}\color{blue}{t}\color{blueviolet}{u}\color{purple}{d}\color{orchid}{y}\color{magenta}{!}}{\hspace{1.5pt}\it\color{black}{Welcome~to~OpenStudy!}}\) \(\it\color{charcoal}{~~~~Please~be~sure~to~read~OpenStudy's~terms~listed~within~the~following~links:}\) \(~\hspace{1.5pt}\large\color{red}{_✧~}\huge\color{orange}{^✧~}\normalsize\color{gold}{✧~~}\Large\color{blue}{/)}\LARGE\color{blue}{_∧}\Large\color{blue}{/)~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~}\hspace{3.5pt}\Large\color{blueviolet}{/)}\LARGE\color{blueviolet}{_∧}\Large\color{blueviolet}{/)~~~~}\hspace{10pt}\large\color{gold}{^✧}\LARGE\color{orange}{_✧}\huge\color{yellow}{^✧}\)\(~~\Large\color{red}{~~_✧~~}\large\rm\color{blue}{O(}\Large\color{blue}{＾}\color{blue}{_ヮ}\hspace{2pt}\Large\color{blue}{＾}\hspace{2pt}\color{blue}{)o}\hspace{160pt}\Large\rm\color{blueviolet}{o(}\Large\hspace{3pt}\color{blueviolet}{＾}\color{blueviolet}{_ヮ}\hspace{2pt}\Large\color{blueviolet}{＾~}\hspace{3pt}\large\color{blueviolet}{)O}\small\color{orange}{~_✧}\Large\color{gold}{~~^✧}\hspace{235.7pt}\underset{\href{https:///openstudy.com/termsandconditions}{\hspace{0pt}\LARGE\it{\color{red}{\bigstar~T}}\color{orange}{e}\color{gold}{r}\color{lime}{m}\color{cyan}{s}\color{blue}{~a}\color{blueviolet}{n}\color{purple}{d}\color{orchid}{~C}\color{magenta}{o}\color{pink}{n}\color{red}{d}\color{orange}{i}\color{gold}{t}\color{lime}{i}\color{cyan}{o}\color{blue}{n}\color{blueviolet}{s}\color{red}{~\bigstar}}}{{\href{https:///openstudy.com/codeofconduct}{\hspace{5.5pt}\large\it{\color{red}{\bigstar~C}}\color{orange}{o}\color{gold}{d}\color{lime}{e~}\color{cyan}{o}\color{blue}{f~}\color{blueviolet}{C}\color{purple}{o}\color{orchid}{n}\color{magenta}{d}\color{pink}{u}\color{red}{c}\color{orange}{t}\color{red}{~\bigstar}}}}\) \(~\small\color{red}{~~~~~~~~_✧~~~~}\hspace{0pt}\large\rm\color{blue}{O(")(")~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~}\hspace{0pt}\large\rm\color{blueviolet}{(")(")O}\small\color{red}{~~~~~~✧}\) \(\Large\color{green}{~~~~~⌒⌒⌒⌒⌒⌒⌒⌒⌒⌒⌒⌒⌒⌒⌒⌒⌒⌒⌒⌒⌒⌒⌒⌒⌒⌒⌒⌒⌒⌒⌒⌒⌒⌒}\)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0@DecentNabeel x^2 +3x +3x +9

DecentNabeel
 one year ago
Best ResponseYou've already chosen the best response.0\[\mathrm{Simplify}\:x^2+3x+3x+9:\quad x^2+6x+9\]

DecentNabeel
 one year ago
Best ResponseYou've already chosen the best response.0\[\mathrm{Simplify}\:\left(x+3\right)\left(x+3\right):\quad \left(x+3\right)^2\]

DecentNabeel
 one year ago
Best ResponseYou've already chosen the best response.0Happy @kayleeq :)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Wait what happened I'm sorry

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Is that all the steps

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Is a common factor for all of the x^2

DecentNabeel
 one year ago
Best ResponseYou've already chosen the best response.0x^2 25 this formula a^2b^2=(ab)(a+b) x^25^2=(x5)(x+5)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Is that all of the steps though I'm so confused

DecentNabeel
 one year ago
Best ResponseYou've already chosen the best response.0tell me why confused

DecentNabeel
 one year ago
Best ResponseYou've already chosen the best response.0\[x^225=\left(x+5\right)\left(x5\right)\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Is that the steps I don't know how to do this I've been at it for forever

DecentNabeel
 one year ago
Best ResponseYou've already chosen the best response.0you know a^2b^2=(ab)(a+b)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0What are the steps can you please show me with the actual numbers please yes but is am so conus fed with this question please help me

DecentNabeel
 one year ago
Best ResponseYou've already chosen the best response.0x^2 25 use this formula:a^2b^2=(ab)(a+b): 25=5^2 x^25^2=(x5)(x+5)

DecentNabeel
 one year ago
Best ResponseYou've already chosen the best response.0MATHEMATICAL FORMULAE Algebra 1. (a + b)2 = a2 + 2ab + b2; a2 + b2 = (a + b)2 − 2ab 2. (a − b)2 = a2 − 2ab + b2; a2 + b2 = (a − b)2 + 2ab 3. (a + b + c)2 = a2 + b2 + c2 + 2(ab + bc + ca) 4. (a + b)3 = a3 + b3 + 3ab(a + b); a3 + b3 = (a + b)3 − 3ab(a + b) 5. (a − b)3 = a3 − b3 − 3ab(a − b); a3 − b3 = (a − b)3 + 3ab(a − b) 6. a2 − b2 = (a + b)(a − b)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Oooooooooo ok I got that see I just needed some explaination now only the second and third polynomial share a common factor is that correct it is x^2

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Ok thank you sooooooooo much
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