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Is this FLVS?
Im doing it rn
alg 1 sem 2 mod 7

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im way behind, was on vacation
maybe, one sec
divide the coefficient of t by 2 6 / 2 = 3 so we have f(x) = (t + 3)^2 - 9 - 20 = (t + 3)^2 - 29
- thats vertex form
ok the general form for veretx is (x - a)^2 + b where (a,b) is the coordinates of the vertex so comparing with our result the vertex is at (-3,-29)
the coefficient od t^2 is positive so that makes the vertex a minimum.
the axis of symmetry is the vertical line going through the point (-3,-29) can you tell me the equation of that line?
yes you can work it out that way. but easier way is to note that vertex has t = -3 so axis of symmetry is t = -3
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i only have 5 minutes
In fact gotta go now - I have to take my daughter home.

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